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3 years ago

(-1,0) and a slope of -2

Mathematics

1 answer:

rodikova [14]3 years ago

4 0

Answer:

y = -2x-2

Step-by-step explanation:

y = mx+b

0 = -1*(-2)+b

0 = 2+b

b = -2

y = -2x-2

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Solve (6-5x)/10-(2x+1)/5+x/3=2x/15

Ulleksa [173]

Multiply2 * x/15 to 2x/15

multiply both sides by 30 which is the LCM of 10, 5, 3, and 15

expand it

simplify 18 - 15x - 12x - 6 + 10x to 12 - 17x

add 17x to both sides

add 4x + 17x to = 21x

divide both sides by 21

simplify 12/21 to 4/7

now simplify

Answer: x = 4/7.

3 0

3 years ago

The temperature fell 4 degrees in the last hour. Now it is 21 degrees. Write an equation to find the temperature it was 1 hour a

Sloan [31]

Answer:

21 + 4 = 25

Step-by-step explanation:

this is the answer because the temperature fell 4 degrees in the last hour.

so we have to add back that 4 to get the answer.

our equation will be 21 + 4 equals 25.

hope this helps!

sakuracherry

6 0

2 years ago

Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46

JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

$M = \frac{50463-38737}{2} = 5863$

Relating the margin of error with the sample size:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.64.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

For this problem, we have that $\sigma = 14300, M = 5863$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$5863 = 1.645\frac{14300}{\sqrt{n}}$

$5863\sqrt{n} = 1.645*14300$

$\sqrt{n} = \frac{1.645*14300}{5863}$

$(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2$

$n = 16$

The sample size was of 16.

7 0

3 years ago

Verify the following identity and show steps<br><br> (Cos2 θ)/(1+sin2 θ)= (cot θ-1)/(cot θ+1)

Paul [167]

Answer:

Verified below

Step-by-step explanation:

We want to show that (Cos2θ)/(1 + sin2θ) = (cot θ - 1)/(cot θ + 1)

In trigonometric identities;

Cot θ = cos θ/sin θ

Thus;

(cot θ - 1)/(cot θ + 1) gives;

((cos θ/sin θ) - 1)/((cos θ/sin θ) + 1)

Simplifying numerator and denominator gives;

((cos θ - sin θ)/sin θ)/((cos θ + sin θ)/sin θ)

This reduces to;

>> (cos θ - sin θ)/(cos θ + sin θ)

Multiply top and bottom by ((cos θ + sin θ) to get;

>> (cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ)

In trigonometric identities, we know that;

cos 2θ = (cos² θ - sin²θ)

cos²θ + sin²θ = 1

sin 2θ = 2sinθcosθ

Thus;

(cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ) gives us:

>> cos 2θ/(1 + sin 2θ)

This is equal to the left hand side.

Thus, it is verified.

5 0

2 years ago

I need help with these two .

stira [4]

Answer:

6 .Cant find the answer there

cos i had 3b( 9c +3a +c )

7. -3x -17y

4 0

2 years ago