<h3>
Answer: Choice C. |x+3| < 5</h3>
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Explanation:
Let's go through each answer choice and solve for x
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Choice A
|x+3| < -5
This has no solutions because |x+3| is never negative. It is either 0 or positive. Therefore, it can never be smaller than -5. So we can rule this out right away.
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Choice B
|x+8| < 2
-2 < x+8 < 2 .... see note below
-2-8 < x+8-8 < 2-8 ... subtract 8 from all sides
-10 < x < -6
We will have a graph where the open circles are at -10 and -6, with shading in between. This does not fit the original description. So we can rule this out too.
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Choice C
|x+3| < 5
-5 < x+3 < 5 .... see note below
-5-3 < x+3-3 < 5-3 .... subtracting 3 from all sides to isolate x
-8 < x < 2
We found our match. This graph has open circles at -8 and 2, with shading in between. The open circles indicate to the reader "do not include this value as a solution".
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note: For choices B and C I used the rule that
turns into
where k is some positive number. For choice A, we have k = -5 which is negative so this formula would not apply.
Shading above (>) the solid (or =) line tells you it is
y ≥ (something)
The only possible choice is
y ≥ (3/2)x - 3
Answer: The value of x is 155/79.
Step-by-step explanation:
13(6x -5 )-x= 13 -2(x +1)
78x - 65- x = 13 -2x -2
77x -65 = 11-2x
79x -65 =11
79x =76
x = 76/79 76/ 79 + 1/1 = 155/79
Answer:
-6f+10g
Step-by-step explanation:
X is an odd number
x+2 is also odd (consider the example x = 3 so x+2 = 3+2 = 5). Adding 2 to any odd number is always odd
Similarly, so is x+6 (since we have x+2+2+2).
And so is x+10 (x+2+2+2+2+2).
So every value in this list is an odd number. The middle most values are x+2 and x+6 which are both odd.
Adding any two odd numbers together yields an even number. For example 3+5 = 8. Divide this even number in half and we may or may not get an odd number (eg: 8/2 = 4 and 6/2 = 3)
So this statement is sometimes true