Answer:
Tooth A
Step-by-step explanation:
Since the larger tooth has to be displayed, knowing that no matter how many zeros you add to the end of a decimal, the value of it will stay the same. 0.23 is 1 digit short that 0.195, so if you just add a 0 to 0.23, it make both of them have a digit in the thousandths place. Now it's easier to solve, 0.230>0.195.
Tooth A should be displayed.
I'm assuming that when you say expanded form, you mean broken down into ones, tens, hundres and so forth.
so, 1203=1000+200+3
Answer:
0.75
Step-by-step explanation:
6 / 8 =
0.75
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
