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3 years ago

Parallelogram ABCD is a rectangle.

Mathematics

2 answers:

umka21 [38]3 years ago

7 0

...............................dwop

seraphim [82]3 years ago

6 0

I think
4y+13=6y-1
-13 -13
4y=6y-14
-6y -6y
-2y=-14
-2y/-2=-14/-2
y = 7

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A tablet and a digital camcorder are both on sale for 30% off. The regular price of the tablet is $185. The regular price of the

Arlecino [84]

Answer:

129.50

Step-by-step explanation:

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3 years ago

Use the Factor Theorem to determine whether x + 1 is a factor of P(x) = 2x³+4x²–2x−8.

Harman [31]

Answer: $2x^2+2x-4-\frac{4}{x+1}$

Not a factor because there is a remainder.

Step-by-step explanation:

Let's use synthetic division to solve this..

-1 ║ 2 | 4 | -2 | -8

║ | -2| -2 | 4

║ 2 | 2| -4 | -4

$2x^2+2x-4-\frac{4}{x+1}$

PS: if anyone knows a better way to do a synthetic division chart please let me know.

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1 year ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

I have five questions and I need some help. please help

Step2247 [10]

The answer to the question

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3 years ago

I need help I did most of them but not sure if there right if you could tell me that would be great. Also can you help me with 9

Andrej [43]

Explanation:

In the given identified the following with reasons.

1. Given

2. Corresponding Angles postulate

3. Reflexive property of congruence

4. AA similarity postulate.

5. Triangle proportionate

6. Cross multiply

7. Distributive property of equality

8. Subtraction property of equality

9. Division property of equality

10. Prove

8 0

3 years ago

Parallelogram ABCD ​ is a rectangle.

Parallelogram ABCD is a rectangle.