Answer:
= 5 − 101i
Step-by-step explanation:
2i(A ∙ E) − C + G
=
2i(-3 − 4i)(8 − 8i) − (13 + i) + (2 + 12i)
=
2i(-24 + 24i − 32i + 32i2) − (13 + i) + (2 + 12i)
=
2i(-24 − 8i − 32) − (13 + i) + (2 + 12i)
=
2i(-56 − 8i) − (13 + i) + (2 + 12i)
=
(-112i − 16i2) − (13 + i) + (2 + 12i)
=
(16 − 112i) − (13 + i) + (2 + 12i)
=
(16 − 112i) + (-13 − i) + (2 + 12i)
=
(16 − 13 + 2) + (-112i − i + 12i)
=
(16 − 13 + 2) + (-112 − 1 + 12)i
= 5 − 101i
Answer:
75.4
Step-by-step explanation:
C=2πr=2·π·12≈75.39822
6 and 4. The answer has to be 20 characters long in order to post so ignore this part.
We know that the first cyclist has traveled 24.2 km at a speed of 10 km/h. Lets use the equation

to find the time of the first cyclist:


So, we know that she has traveled for 2.42 hours.
We also know that after she has traveled for 2.42 hours another<span> cyclist sets out in the same direction, so if </span>

represents the time of our first cyclist, <span>the time of our second cyclist will be </span>

.
Now we are going to use the equation

to relate the speeds and times of the two cyclist:
For the first one:

equation (1)
For the second one:

equation (2)
Replace (1) in (2)

The only thing left now is solve for

:




We can conclude that the second cyclist will catch up the first cyclist after
3.63 hours.