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iren [92.7K]
3 years ago
11

BÉ is an angle bisector of ZABC.

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0
Angle bisector makes the two split parts equal to each other:
2x+20=4x-6
2x+26=4x
26=2x
x=13
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Use these complex numbers from the table to write the following expression as a complex number in standard form.
xxTIMURxx [149]

Answer:

=  5 − 101i

Step-by-step explanation:

2i(A ∙ E) − C + G

=

2i(-3 − 4i)(8 − 8i) − (13 + i) + (2 + 12i)

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2i(-24 + 24i − 32i + 32i2) − (13 + i) + (2 + 12i)

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2i(-24 − 8i − 32) − (13 + i) + (2 + 12i)

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2i(-56 − 8i) − (13 + i) + (2 + 12i)

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(-112i − 16i2) − (13 + i) + (2 + 12i)

=

(16 − 112i) − (13 + i) + (2 + 12i)

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(16 − 112i) + (-13 − i) + (2 + 12i)

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(16 − 13 + 2) + (-112i − i + 12i)

=

(16 − 13 + 2) + (-112 − 1 + 12)i

=  5 − 101i

5 0
3 years ago
Find the circumference of the circle and show work
Jlenok [28]

Answer:

75.4

Step-by-step explanation:

C=2πr=2·π·12≈75.39822

3 0
2 years ago
Read 2 more answers
A dog trainer compared mean numbers of lessons for two<br> groups of dogs to learn a new trick.
d1i1m1o1n [39]

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D

Step-by-step explanation:

4 0
3 years ago
What are two factors of 24 that add to be 10? separate each factor by a comma
grigory [225]
6 and 4. The answer has to be 20 characters long in order to post so ignore this part.
6 0
3 years ago
A bicyclist heads east at 10km/h. After she has traveled 24.2 kilometers, another cyclist sets out in the same direction going 3
Alona [7]
We know that the first cyclist has traveled 24.2 km at a speed of 10 km/h. Lets use the equation time= \frac{distance}{speed} to find the time of the first cyclist:
t= \frac{24.2}{10}
t=2.42
So, we know that she has traveled for 2.42 hours.
 
We also know that after she has traveled for 2.42 hours another<span> cyclist sets out in the same direction, so if </span>t represents the time of our first cyclist, <span>the time of our second cyclist will be </span>t-2.42.

Now we are going to use the equation distance=(speed)(time) to relate the speeds and times of the two cyclist:
For the first one:
distance=10t equation (1)
For the second one:
distance=30(t-2.42) equation (2)

Replace (1) in (2)
10t=30(t-2.42)
The only thing left now is solve for t:
10t=30t-72.6
-20t=-72.6
t= \frac{-72.6}{-20}
t=3.63

We can conclude that the second cyclist will catch up the first cyclist after 3.63 hours.


4 0
3 years ago
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