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Makovka662 [10]
2 years ago
10

Find the fourth degree polynomial function with zeros 6,-6,6i

Mathematics
2 answers:
Cloud [144]2 years ago
7 0

Answer:

1) -6

2) 6

3) -6i

Step-by-step explanation:

tbese are your answer flw me

Irina-Kira [14]2 years ago
3 0

Answer:

See below

Step-by-step explanation:

6 is a solution to x-6=0, -6 is a solution to x+6=0, and 6i is a solution to x^2+36=0. So, we can do (x-6)(x+6)(x^2+36) to get (x^2-36)(x^2+36) which gets us x^4-1296. Therefore, the fourth degree polynomial with zeroes 6, -6, 6i is x^4-1296

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<u>Answer:</u>

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<u>Steps:</u>

5.

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6.

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3 years ago
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4 0
3 years ago
Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

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5 0
3 years ago
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Enjoy!=)</span></span></span>
8 0
3 years ago
If angle symbol1 and angle symbol2 are complementary angles and if the measure of angle symbol1 is 5454degrees° more than the me
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7 0
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