47/ 3 rad= 2820
have a great day
Answer:
Step-by-step explanation:
Let the base camp is point A and boats' locations after two hours are points B and C.
By connecting the three points together we get a triangle ABC with sides:
- AB = 50*2 = 100 km
- AC = 70*2 = 140 km
The angle between AB and AC is:
- 60 + 50 = 110 degrees (opposite directions from south)
We are looking for the distance BC, which can be found by using the law of cosines:
- BC² = AB² + AC² - 2AB*AC*cos ∠BAC
- BC² = 100² + 140² - 2*100*140*cos 110°
- BC² = 39176.56 (rounded)
- BC = √39176.56 = 197.93 km (rounded)
The distance between the boats is 197.93 km.
Answer:
The measure of arc BD is 147°
Step-by-step explanation:
we know that
If segment AB is perpendicular to segment CD
then
The measure of the inner angle CPA is a right angle (90 degrees)
Remember that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.
so
m∠CPA=(1/2)[arc AC+arc BD]
substitute the given values
90°=(1/2)[33°+arc BD]
180°=33°+arc BD
arc BD=180°-33°=147°
Only like sedans: 25- 15 = 10
Only like hatchbacks: 40-15 = 25
Like both: 15
Like none of them: 100-10-25-15 = 50
Dislike sedans: 100 - 10-15 = 75
Dislike hatchbacks: 100-25-15 = 60
So dislikes: sedans>hatchbacks
Answer:
12.50
Step-by-step explanation:
18.20-5.60= 12.50
