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White raven [17]
3 years ago
14

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.

Mathematics
2 answers:
zlopas [31]3 years ago
4 0
In a function, each x-coordinate can be used only once.
If you have two points, one above the other on the same vertical line, it is not a function.
You are correct.
Fed [463]3 years ago
4 0
The upper, right-hand graph represents a function.  Why?  Because there is never more than one value of y for any given x.

If you use the vertical line test on the other 3 problems, you'll see that for some x, the line goes thru more than just one black dot.
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What is the simplified form of 3x - 6/ x -2 ?
nlexa [21]
3x-6/x-2
3(x-2)/x-2
3

3 is the simplified form 
5 0
3 years ago
Read 2 more answers
Please show your work how you solved this ! Please answer this !!
ValentinkaMS [17]

Answer:

-5xa^2-7a^3+7a^2+4

Step-by-step explanation:

6 0
3 years ago
Solve −2(−4n + 1)+5(25n − 8)=−62. <br><br><br><br> n= ?
In-s [12.5K]
N= -20/133

Step 1: Simplify both sides of the equation.
−
2
(
−
4
n
+
1
)
+
5
(
25
n
−
8
)
=
−
62
(
−
2
)
(
−
4
n
)
+
(
−
2
)
(
1
)
+
(
5
)
(
25
n
)
+
(
5
)
(
−
8
)
=
−
62
(Distribute)
8
n
+
−
2
+
125
n
+
−
40
=
−
62
(
8
n
+
125
n
)
+
(
−
2
+
−
40
)
=
−
62
(Combine Like Terms)
133
n
+
−
42
=
−
62
133
n
−
42
=
−
62
Step 2: Add 42 to both sides.
133
n
−
42
+
42
=
−
62
+
42
133
n
=
−
20
Step 3: Divide both sides by 133.
133
n
133
=
−
20
133
n
=
−
20
133
5 0
2 years ago
Read 2 more answers
Factor completely 2x3 + x2 - 18x - 9
melisa1 [442]
Factor the following:
2 x^3 + x^2 - 18 x - 9

Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)

Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)

x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)

Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):

Answer:  (x - 3) (x + 3) (2 x + 1) thus the Answer is C.
7 0
3 years ago
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Ldentify the following sections of the textbook.
Tema [17]
I don’t know what the drop down options are so I can’t answer your question. Sorry but can u pls help answer my question I just posted? That would be very helpful thx!
7 0
3 years ago
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