Answer:
1. -1.25
2. 0.1056
Step-by-step explanation:
We are given that
mean=129
S.D=0.8
1.
The z-score can be found as
z=(x-mean)/S.D
z=(128-129)/0.8
z=-1/0.8
z=-1.25
Thus, a z-score corresponding to 128 fl. Oz. milk is -1.25.
2.
We have to find P(X<128).
A z-score is already found in part 1, So,
P(X<128)=P(Z<-1.25)
P(X<128)=P(-∞<Z<0)-P(0<Z<-1.25)
Using normal area table, we get P(0<Z<-1.25)=0.3944
P(X<128)=0.5-0.3944
P(X<128)=0.1056
Thus the probability that a randomly selected jug will contain less than 128 fl. Oz. of milk is 0.1056 or 10.56%
100 and 110.
You would have to add 100 to both sides. This is because to complete the square, you need to take half of the x term and square it.
Answer: 6.46 is your answer
Step-by-step explanation:
20 + 12x = 56
12x = 56 - 20
12x = 36
x = 36/12
x = 3
Bethany's monthly gym fee is $ 20
Bethany also pays $ 3 for a towel fee each visit
Answer:
The area of the large sail of the sailboat is 144 feet² .
Step-by-step explanation:
Given as :
The measure height of the large sail = 24 feet
The measure of base of the sail = 12 feet
The area of the sail = A feet²
Now, <u>Since The sail of the sailboat is in the form of right angle triangle</u>
So, From The area right angle triangle
Area of right angle Triangle = × height × base
Area = × height of the sail × base of sail
Or, A = × 24 × 12
Or , A =
∴ A = 144 feet²
So, the area of sail = 144 feet²
Hence The area of the large sail of the sailboat is 144 feet² . Answer