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kherson [118]
3 years ago
10

I need help please help me​

Mathematics
2 answers:
alexdok [17]3 years ago
3 0
It’s 3 because 15\5 is 3
swat323 years ago
3 0

Answer:

3 stamps for $5

Step-by-step explanation:

$5 times 3 is $15

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Cali soccer practice was one hour and 15 minutes long it ended at 7:15 PM what time did practice start
madreJ [45]

Answer:

Soccer practice started at 6:00, because 7:15 - 1:15 = 6:00

5 0
3 years ago
*WILL GIVE BRAINLIST TO WHO EVER IS RIGHT!*
Scorpion4ik [409]

Answer:g(X)=2x^2-10

Step-by-step explanation:

If a function f(x) is translated 'c' units down then the equation of the translated function be f(x)-c

Here, f(x) is translated 2 units down to obtain g(x).

Hence, we have

g(x)=f(x)-2

   =2x^2-8-2

  =2x^2-10

8 0
2 years ago
Use the FOIL method to evaluate the expression
In-s [12.5K]
So u multiply each term in the first parentheses by each term in the second parentheses.

√5 √5 + 6√5-3√5 - 3x6
Now you multiply the numbers which will get u:
5+6√5 - 3√5 - 18
Then subtract:
-13 +3√5 that’s your answer
7 0
2 years ago
Which number is the common difference of the sequence -92,-74,-54,-38,-20?
Mkey [24]
The common difference if there is one is the constant difference that occurs between any term and the term before it.... in this case:

There is no common difference, 

dx=18,20,16,18  the difference or velocity is not constant...

d2x=2, -4,2  the acceleration is not constant...

d3x=-6,6  the thrust is not constant  

Now we might be tempted to say that:

d4x=12 and say that that is constant and we COULD make a quartic equation fit all the data points, but without further data points in the sequence there is no mathematical proof that the quartic equation would produce accurate data points outside of the range given...

And solving a system of five equations for five unknowns is tedious for such a problem...a^4+bx^3+cx^2+dx+e=y

8 0
3 years ago
Read 2 more answers
Solving Exponential Equations (lacking a common base)<br><br>(0.52)^q=4
bulgar [2K]

Answer:

q = log4 / log0.53

q = -2.189

Step-by-step explanation:

(0.53)^q = 4

Taking log of both sides!

q log 0.53 = log 4

q = log 4 / log 0.53

q = 0.602 / -0.275

q = - 2.189

This can be checked to confirm correctness.

Substituting q = -2.189

(0.53)^ -2.189 = 1/ 0.249

= 4.01 Proved!

(Note that the "1" is because of the negative sign)

8 0
3 years ago
Read 2 more answers
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