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3 years ago

Please help look at picture round to the nearest tenth

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

I see that its a kuta software page. Search up the name of the topic at the top left and then at the end put kuta software. It works like a charm.

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The diagram shows 2 congruent regular polygons joined together. Work out the number of sides of each polygon. The exterior angle

Svetlanka [38]

Answer: There are five sides in a polygon.

Step-by-step explanation:

Since we have given that

Measure of exterior angles = 72°

We need to find the number of sides of polygon.

As we know the formula for "Number of sides of polygon".

Number of sides is given by

$\frac{360^\circ}{72^\circ}\\\\=5$

Hence, there are five sides in a polygon.

5 0

4 years ago

Read 2 more answers

Substitute the variable and solve the problem

Ann [662]

Answer:

don't know the answer but hope this helps

Substituting for a Variable

If you know the value that the variable is equal to, you can substitute that value in for the variable in the expression! Let's look at an example. Since we know that x=5, we can directly substitute or replace the x in the expression x+3 with a 5 to solve for y!

8 0

3 years ago

What is the proportional relationship show in 8 tablespoons of honey for every 10 cups of flour.

elena55 [62]

Answer:

4 : 5

Step-by-step explanation:

8 : 10

4 : 5

hope this was helpful : )

6 0

3 years ago

Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes

yaroslaw [1]

Answer:

$\frac{y^{2}}{25}-\frac{x^{2}}{3}=1$

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: $(0,-\sqrt{28}),(0,\sqrt{28})$

eje conjugado = $2\sqrt{3}$

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

$\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1$

de los focos podemos obtener que:

$c=\sqrt{28}$

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

$b=\sqrt{3}$

podemos utilizar la siguiente fórmula para obtener a:

$c^{2}-a^{2}=b^{2}$

si despejamos a en la ecuación obtenemos lo siguiente:

$a=\sqrt{c^{2}-b^{2}}$

ahora podemos sustituir los valores:

$a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}$

$a=\sqrt{28-3}$

$a=\sqrt{25}$

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

$\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1$

$\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1$

$\frac{y^{2}}{25}+\frac{x^{2}}{3}=1$

si graficamos la hipérbola, queda como en el documento adjunto.

7 0

3 years ago

For positive acute angles A and B it is known that tan A 15/8 and Cos B 12/37 find the value of Cos (A+b) being in simplest form

weqwewe [10]

Answer:

Step-by-step explanation:

Cos(A + B) = Cos(A)*Cos(B) - Sin(A)*Sin(B)

Find The Hypotenuse of A

Tan(A) = Opposite / Adjacent

Tan(A) = 15/8

Opposite = 15

Adjacent = 8

Hypotenuse = c

c^2 = opposite^2 + Adjacent^2

c^2 = 15^2 + 8^2

c^2 = 225 + 64

c^2 = 289

sqrt(c^2) = sqrt(289)

c = 17

Find the opposite of B

Adjacent = 12

Hypotenuse = 37

Opposite = b

adjacent^2 + opposite^2 = hypotenuse^2

12^2 + b^2 = 37^2

144 + b^2 = 1369

b^2 = 1369 - 144

b^2 = 1335

b = 35

Definitions

Sin(A) = Opposite / hypotenuse = 15/17

Sin(B) = opposite / hypotenuse = 35/37

Cos(A) = 8/17

Cos(B) = 12/37

Answer

Cos(A + B) = Cos(A)*Cos(B) - Sin(A)*Sin(B)

Cos(A + B) = 8/17 * 12/37 - 15/17*35/37

Cos(A + B) = 96/629 - 525/629

Cos(A + B) = -429/629

6 0

3 years ago