Question

A zoo train ride costs $4 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who took the ride was 27, and the total money collected was $60. What was the number of children and the number of adults who took the train ride that day, and which pair of equations can be solved to find the numbers?
11 children and 16 adults
Equation 1: a + c = 27
Equation 2: 4a + c = 60
16 children and 11 adults
Equation 1: a + c = 27
Equation 2: 4a + c = 60
11 children and 16 adults
Equation 1: a + c = 27
Equation 2: 4a − c = 60
16 children and 11 adults
Equation 1: a + c = 27
Equation 2: 4a − c = 60

Answer 1

A+c=27 and 4a+c=60  (this is your pair of equations)

Solving the first for a, a=27-c, now using this value of a in the second equation gives you:

4(27-c)+c=60 perform indicated multiplication on left side

108-4c+c=60  combine like terms on left side

108-3c=60  subtract 108 from both sides

-3c=-48  divide both sides by -3

c=16, and since a=27-c

a=27-16=11

So there were 16 children and 11 adults.

Answer 2

Hi there The answer is 16 children and 11 adults Equation 1: a + c = 27 Equation 2: 4a + c = 60 Check 11+16=27 4×(11)+1×(16)=60 Correct Good luck!