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murzikaleks [220]
3 years ago
15

What is the value of the expression? Drag and drop the answer into the box to match the expression. 0.9(1/2−2)+0.6

Mathematics
2 answers:
arsen [322]3 years ago
8 0
Just use pemdas....
-0.75 is the solution.

 distributed the 0.9 to the .5 converted fraction to decimal and the 2,  keep the parenthesis and subtract the 0.45 with the positive 1.8 which equals -1.35. Then add-1.35 to 0.6 and then you get -0.75 is the solution.


mrs_skeptik [129]3 years ago
6 0
Should be, -0.7, if you follow PEMDAS
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48 points hey can you help 1-1+1 :)))) your welcome
REY [17]
1-1+1
Therefore:0+1
Ans: 1
3 0
2 years ago
The regular octagon in the ceiling of this cathedral has a radius of 10.5 feet and a perimeter of 64 feet. What is the length of
Alexeev081 [22]
The apothem of a polygon is a line made from the center to the midpoint of any side of the polygon. The radius, on the other hand, is the line from the center to any corner of the polygon. If you illustrate the problem, you can form a right triangle where the hypotenuse is the radius, and the other two legs are the apothem and half of one side of the polygon. 

Perimeter of octagon = 8*length of each side = 64
length of each side = 8 ft

Therefore,
Apothem = √(10.5^2 - (8/2)^2) = 9.71 ft
5 0
2 years ago
Read 2 more answers
art teacher has 450 sheets of construction paper on first day of school. students used 18 sheets during each school day. how man
AVprozaik [17]

Answer:

25

Step-by-step explanation:

025

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7 0
3 years ago
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
3 years ago
Help me please help with this problem
vodomira [7]
It would be x=-4 have a good day
5 0
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