Hi student, let me help you out! :)
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
We are asked to simplify the expression .
That's exactly what we need to do - combine like terms.
So, we subtract:
Which gives us:
Hope it helps you out! :D
Ask in comments if any queries arise.
#StudyWithBrainly
~Just a smiley person helping fellow students :)
Answer:
∠ 6 = 45°
Step-by-step explanation:
∠ 6 and ∠ 7 are alternate angles and are congruent, thus
4x - 15 = x + 30 ( subtract x from both sides )
3x - 15 = 30 ( add 15 to both sides )
3x = 45 ( divide both sides by 3 )
x = 15
Thus
∠ 6 = 4x - 15 = 4(15) - 15 = 60 - 15 = 45°
Answer:
A/15=5
so multiply 15*5
you would get 75
therefore a=75
Step-by-step explanation:
Step-by-step explanation:
I think this should be the expression
X = 14 + 50
Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N()' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N()' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.
Formula for probability of an event E can be observed as:
So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.