Answer:
Population of fish in 2010 = 1,646 fish (Approx.)
Step-by-step explanation:
Given:
Population of fish in 2002 = 2100 fish
Decrease rate = 3% per year
Find:
Population of fish in 2010
Computation:
Number of year = 2010 - 2002
Number of year = 8 year
A = P[1+r]ⁿ
Population of fish in 2010 = Population of fish in 2002[1+(-3%)]ⁿ
Population of fish in 2010 = 2100[1-0.03]⁸
Population of fish in 2010 = 2100[0.97]⁸
Population of fish in 2010 = 2100[0.7837]
Population of fish in 2010 = 1645.77
Population of fish in 2010 = 1,646 fish (Approx.)
Answer:
84.823
Step-by-step explanation:
volume = 1/3 (pi)(r2)(H)
Make an equation:
x= 16% x 50
x= 16 50
---- x ---- Cross Multiply
100 1
x= 16
------ = 8
Answer:
68.5
Step-by-step explanation:
Arc ABE = 360 - 2x
Arc AE = 2x
half the difference between the two arcs is 43
43 = 
[360 -2x - (2x)]
At least 30 ..................
