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Aleksandr-060686 [28]
2 years ago
14

HERE ARE 2 QUESTIONS PLS HELP ASAP ITS MATH

Mathematics
1 answer:
leva [86]2 years ago
7 0
<h2><u>Answer:</u></h2><h3>6.) \boxed{A}</h3><h3>7.) \boxed{D}</h3><h2 /><h2><u>Solution Steps:</u></h2>

______________________________

<h3>6.) Solve each problem:</h3>
  • 3 ÷ 8=0.375
  • 4 ÷ 12=0.333333333
  • 2 ÷ 6=0.333333333
  • 10 ÷ 30=0.333333333

 - So looking at this most of them equal 0.333333333, which in fraction form is \frac{1}{3}, so 3 ÷ 8 must be the answer.

<h3 /><h3>7.) Solve each problem: </h3>
  • 25 ÷ 8=3.125
  • \frac{25}{8}=3.125
  • 3\frac{1}{8}=\frac{25}{8}=3.125
  • 8 ÷ 25=0.32

<em>  - So looking at each problem answer, most of them are 3.125, except for 8 ÷ 25.</em>

______________________________

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3(1 – 2x) &gt; 3 – 6х help
coldgirl [10]

Answer:

<h2>\huge \: x \in ∅</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • inequality
  • distribution
  • PEMDAS
<h3>given:</h3>
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<h3>to solve:</h3>
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<h3>let's solve:</h3>

step - 1  : define\\ 3(1  -  2x) > 3 - 6x

step -  2: distribute\\ 3  -  6x > 3 - 6x

step - 3  :  \\ add \: 6x \: to \: both \: sides

3  -  6x  + 6x> 3 - 6x + 6x

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\therefore \: the \: statement \: is \: false \: for \: any \: value \: of \: x \: because \: both \: sides \: are \: identical

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x \in ∅

4 0
2 years ago
Identify the terms,like terms,coefficient and constants
BartSMP [9]
Terms: -4j, -2, -5j, 6
Like Terms: -4j and -5j, -2 and 6
Coefficients: -4, -5
Constants: -2, 6
6 0
3 years ago
A maritime flag is shown. What is the area of the shaded part of the flag? Explain
Rom4ik [11]

Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
2 years ago
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