Answer: 10% (v/v).
Explanation:
V - unit is litre
m/m - by mass concentration
m/v - unit of density
v/v - concentration by volume
Answer:
Hence volume of oxygen gas measured at 0oC and 1atm, ineeded to burn completely 1L of propane gas (C3H8) under the same conditions is 5L.
Explanation:
hope it will help you
Answer:
Density of Ar gas under the given condition is 1.52 g/L
Explanation:
Density in grams/liter = (mass of Ar gas present in flask)/(volume of flask)
We know, number of moles = (mass)/(molar mass)
Molar mass of Ar = 39.948 g/mol
So, mass of 0.228 mol of Ar = ![(0.228\times 39.948)g=9.11g](https://tex.z-dn.net/?f=%280.228%5Ctimes%2039.948%29g%3D9.11g)
Volume of flask = 6.00 L
So, density of gas inside flask = ![\frac{9.11g}{6.00L}=1.52g/L](https://tex.z-dn.net/?f=%5Cfrac%7B9.11g%7D%7B6.00L%7D%3D1.52g%2FL)
Hence, density of Ar gas under the given condition is 1.52 g/L