P1V1/T1=P2V2/T2 P2=1/2 P1 V1=1 T1=298K
1 P1/298= (1/2) P1V2/373 cross P1
1/298=1/2V2/373
1/298=1/V2 746
v2=746/298
V2=2.5L
Answer: (Assuming we’re going by degrees Fahrenheit) I’d say 140.
Explanation: -40 would be beyond freezing point for water which is 32 degrees Fahrenheit and 40 would nearly be freezing point. For water to transform into its gas phase, the temperature would need to be greater. Therefore, 140 degrees Fahrenheit makes the most sense.
Although I did search it up and 212 degrees Fahrenheit (100 degrees Celsius) is the proven temperature at which water transforms into water vapor so... not sure if there’s more to the question or I’m interpreting the question wrong.
Answer: is A
Reason: because the rest are common...
Answer:
8.937g/cm³
Explanation:
To answer this question we need to know that, in 1 unit FCC cell you have:
Edge length = √8 * R
<em>Volume = 8√8 * R³</em>
<em>And there are 4 atoms per unit cell</em>
<em />
<em>Mass of 4 atoms in g:</em>
4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g
<em />
<em>Volume in cm³:</em>
0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm
Volume = 8√8 * (1.278x10⁻⁸cm)³
Volume = 4.723x10⁻²³cm³
And density is:
4.221x10⁻²²g / 4.723x10⁻²³cm³ =
<h3>8.937g/cm³</h3>
Answer:
2.8M
Explanation:
The following data were obtained from the question:
Volume of stock solution (V1) = 40mL
Molarity of the stock solution (M1) = 7M
Volume of diluted solution (V2) = 100mL
Molarity of diluted solution (M2) =?
Using the dilution formula, we can easily find the molarity of the diluted solution as follow:
M1V1 = M2V2
7 x 40 = M2 x 100
Divide both side by 100
M2 = (7 x 40)/100
M2 = 2.8M
Therefore, the molarity of the diluted solution is 2.8M
