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vitfil [10]
3 years ago
5

Voltaic cells and electrolytic cells are similar because:

Chemistry
1 answer:
Murrr4er [49]3 years ago
8 0
Both cells use a salt bridge to keep the electrons flowing within the cells
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Using the brønsted theory, classify the compounds as either an acid or a base
Natali5045456 [20]

Answer:

all the below are ACIDS

Explanation:

1.HCOO- Formate

  HCOO- is a conjugate base.

2.HNO3- Nitric Acid

  Acid

3.CH3COOCH3: Methyl acetate

   Acid

4. HCOOH: Formic Acid

   Acid

Hope  it helps..pls mark as brainliest!

8 0
3 years ago
How many moles are in 337 grams of tellurium?
MaRussiya [10]

about 43001 is it i think

3 0
3 years ago
Which element is oxidized in the reaction below? fe(co)5 (l) + 2hi (g) fe(co)4i2 (s) + co (g) + h2 (g)?
DanielleElmas [232]
Oxidation state of I is (-1) and for CO it is zero. Let's assume that the oxidation state of Fe in Fe(CO)₄I₂<span> (s) is x. For whole compound, the charge is zero.

Sum of oxidation numbers in all elements = Charge of the compound.

Here we have 1Fe , 4CO and 2I
hence we can find the oxidation state as;
 x + 4*0 + 2*(-1) = 0
 x + 0 - 2            = 0
                   x     = +2
Hence the oxidation state of Fe in product </span>Fe(CO)₄I₂ (s) is +2.

Same as we can find the oxidation state (y) of Fe in Fe(CO)₅(s).
y + 5*0 = 0
   y        = 0

Since oxidation state of Fe increased from 0 to +2, the oxidized element is Fe in the given reaction.
5 0
3 years ago
i have a crossword thing that i got from school and one of the clues is: If there are two equal and opposite forces on something
cluponka [151]
I would assume the answer is called attractive
6 0
2 years ago
Read 2 more answers
An object has a mass of 20g and occupies a volume of 40 ml. Calculate the Density of the object.
Vsevolod [243]

Answer:

<h3>The answer is 0.5 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{20}{40}  \\

We have the final answer as

<h3>0.5 g/mL</h3>

Hope this helps you

3 0
3 years ago
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