All categories

4 years ago

How do you correctly read a graduated cylinder

Chemistry

1 answer:

Usimov [2.4K]4 years ago

7 0

See where the liquid or whatever you're measuring meets with the numbers! And thats your answer!

You might be interested in

What map symbol is associated with most of northern africa

pishuonlain [190]

From another answer, it is most likely E. Horizon. Hope this helps!

7 0

3 years ago

Read 2 more answers

Calculate the concentration of H3O+ of a solution if the concentration of OH- at 25°C is 3.8 × 10-5 M and determine if the solut

sergejj [24]

Answer:

[H₃O⁺] = 2.63×10⁻¹⁰ M

As pH = 9.57, the solution is basic

Explanation:

We must know this knowledge:

[OH⁻] . [H₃O⁺] = 1×10⁻¹⁴

3.8×10⁻⁵ . [H₃O⁺] = 1×10⁻¹⁴

[H₃O⁺] = 1×10⁻¹⁴ / 3.8×10⁻⁵ → 2.63×10⁻¹⁰ M

Let's determine the pH to state if the solution is acidic or basic

pH < 7 → acidic ; pH > 7 → basi

pH = - log [H₃O⁺]

pH = - log 2.63×10⁻¹⁰ → 9.57

8 0

3 years ago

The hydrogen atoms of a water molecule are bonded to the oxygen atom by ________ bonds, whereas neighboring water molecules are

zloy xaker [14]

<span>d.polar covalent; hydrogen</span>

3 0

3 years ago

Read 2 more answers

A tank contains a mixture of helium, neon, and argon gases. If the total pressure in the tank is 490. mmHg and the partial press

OleMash [197]

Answer: The partial pressure of neon is 173 mmHg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_A+p_B+p_C$

Given : $p_{total}$ =total pressure of gases = 490 mm Hg

$p_{He}$ = partial pressure of Helium = 215 mmHg

$p_{Ar}$ = partial pressure of argon = 102 mm Hg

$p_{Ne}$ = partial pressure of neon= ?

$p_{total}=p_{He}+p_{Ar}+p_{Ne}$

$490=215+102+p_{Ne}$

$p_{Ne}=173mmHg$

Thus partial pressure of neon is 173 mmHg

5 0

3 years ago

Part A How much time (in minutes) will it take for the water heater to heat the 5.5 L of water from 23 ∘C to 43 ∘C? (Assume that

harina [27]

Answer:

Time = t = 30.01 minutes

Explanation:

The missing part of the question is that "The water heater power rating is 255 Watts, where 1 Watt = 1 J/s.

Firstly, calculating the work done by water heater to heat 5.5 L of water from 23° C to 43°C.

Work Done = Q = m C ΔT

where,

Q = Heat Transfer

m = mass of water

m = Density x Volume = 1 g/mL x 5.5 L = 1000g/L x 5.5L = 5500 g

ΔT = Temperature Difference = 43-23 = 20°C

C = Heat Capacity of Water = 4.186 J/g °C

Therefore,

$Q = (5500g)(4.186J/gC) (20C)\\Q = 460460 J$

Since, Power can be given as Work done per unit time,

$P = \frac{W}{t}$

or, in this case,

$P = \frac{Q}{t}\\$

Here,

P = 255W or P = 255J (Since 1W = 1J)

$P=\frac{Q}{t}\\255 = \frac{460460}{t}\\t = \frac{460460}{255}\\t = 1805.72 s\\t = \frac{1805.72}{60}\\t = 30.01 min$

3 0

3 years ago