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stich3 [128]
3 years ago
12

if excess nitrogen gas reacts with 600 cm³ of hydrogen gas at room conditions , calculate the maximum volume of ammonia produced

from the reaction? the chemical question is N2 + 3H2 = 2NH3​
Chemistry
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

400 cm³ of ammonia, NH₃.

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 cm³ of H₂ reacted to produce 2 cm³ of NH₃.

Finally, we shall determine the maximum volume of ammonia, NH₃ produced from the reaction. This can be obtained as illustrated below:

From the balanced equation above,

3 cm³ of H₂ reacted to produce 2 cm³ of NH₃.

Therefore, 600 cm³ of H₂ will react to produce = (600 × 2)/3 = 400 cm³ of NH₃.

Thus, 400 cm³ of ammonia, NH₃ were obtained from the reaction.

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How many grams of water are made from the reaction of 4.0 grams of hydrogen gas with the given reaction 2H2+O2--->2H2O
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Answer:

The mass of water is 36 g.

Explanation:

Mass of hydrogen = 4 g

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Solution:

First of all we will write the balance chemical equation:

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Number of moles of hydrogen = mass / molar mass

Number of moles of hydrogen = 4 g/ 2 g/mol

Number of moles of hydrogen = 2 mol

Now we compare the moles of water with hydrogen from balance chemical equation.

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Mass of water = moles × molar mass

Mass of water =  2 mol × 18 g/mol

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