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Eva8 [605]
3 years ago
12

The graph of the function f(x) = (x − 3)(x + 1) is shown. Which describes all of the values for which the graph is positive and

decreasing?
Mathematics
1 answer:
bija089 [108]3 years ago
3 0

Answer:

All real values of x where x < −1

Step-by-step explanation:

Solve the function as an inequality:

(x-3)(x+1)>0

There are two cases in this:

Both factors are greater than 0.

x-3>0 and x+1>0

x>3 and x>-1

The intersection is x >3

OR

Both factors less than 0.

x-3<0 and x+1<0

x< 3 and x<-1

The intersection is x< -1

We have obtained that the function is positive for the intervals  x < -1 and x > 3. But in one of those intervals the function is decreasing and in the other is increasing.

The answer is: all real values of x where x < −1 ....

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In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

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What type of function is described by the equation y=3+x?
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an engineer has a 54 inch wire that she has to cut into two pieces so that one piece is 8 inches shorter than the other find the
Brilliant_brown [7]

Hey there!!

Let's take the length of the bigger piece as x inches

Then, the length of the smaller piece would be x - 8 inches

The sum of these lengths would be 54 inches

... x + x - 8 = 54

... 2x - 8 = 54

... Add 8 on both sides

... 2x = 62

... Divide 2 on both sides

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Hence, the length of the bigger piece = 31 inches

The length of the smaller piece would be = 31 - 8 = 23 inches

Hope my answer helps!!

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no way dude really? thats so cool

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