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____ [38]
4 years ago
9

R:{(1,2),(1,−2),(−2,3)} Is this a function?

Mathematics
1 answer:
sdas [7]4 years ago
7 0

Answer:

No, it is not a function because one of the x values have two different y values

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100% probability. the probability of an event is 1 (or 100%) if and only if the event can never occur.
Ierofanga [76]
True us the answer too your question.
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4 years ago
What is the volume of a cylinder with base radius 2 and height 6
jenyasd209 [6]

Answer:

Volume of the cylinder is 75.43

Step-by-step explanation:

Volume of Cylinder is \pi r^{2} h

where r is base radius = 2 and h is the height = 6

(22/7) × 2² × 6

= (22/7) × 4 × 6

= (22/7) × 24

= 528/7

= 75.43

4 0
3 years ago
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Scrat [10]
The answer is A, I’m pretty sure
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3 years ago
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Marie made the box plot below to display a set of data. Which set of data could the box plot represent?
Assoli18 [71]

Answer:

  see below

Step-by-step explanation:

First of all, you want to find the data set the matches the extreme values of 5 and 35. That eliminates the 2nd and 4th choices.

Then you want to find the data set that has a median of 15. The first data set has a middle value (median) of 20, so that choice is eliminated.

The data set of the 3rd choice matches the box plot extremes, median, and quartile values.

7 0
3 years ago
Pls help me!!
vlada-n [284]

Answer:

<h3>Q1</h3>

The graph of y = f(x), has vertex at (1, -2)

<u>The vertex of a function f(x - 3) is going to be:</u>

  • (1 - 3, -2) = (-2, -2)
<h3>Q2</h3>
  • <em>The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).</em>

The axis of symmetry is at the same distance from the symmetric points.

x = 5 is a vertical line. The point (8, -7) is 3 units to the right. So the mirror point will be 3 units to the left and have same y-coordinate: x = 5 - 3 = 2

The point is (2, -7)

<h3>Q3</h3>

The graph in blue is the translation of the red to the left by 2 units.

<u>So the equation is:</u>

  • y = f(x + 2)
<h3>Q4</h3>

y = h(x) is graphed

  • h(7) = 5
  • h(h(7)) = h(5) = -1
<h3>Q5</h3>

The graph of the function y = u(x) given

This is a odd function.

The coordinates of u(x) and u(-x) add to zero because u(-x) = -u(x)

<u>Therefore:</u>

  • u(-2.72) + u(-0.81) + u(0.81) + u(2.72) =
  • [u(-2.72) + u(2.72)] + [u(-0.81) + u(0.81)] =
  • 0 + 0 = 0
3 0
3 years ago
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