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3 years ago

14

You want to frame a picture that is 5 in by 7 in with a 1 in wide frame. What is the perimeter of the outside edge of the frame?

1 answer:

r-ruslan [8.4K]3 years ago

4 0

94 if your using the whole frame the math is 5×7=35 we have 2 sides do times 35 by 2 35×2=70 then we do 1×7=7 for the outside of the game then do 7 times 2 b/c you have 2 sides the do your final side by doing 5×1=5 then times that by 2 and you get 10 .70+14+10=94

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For which values of x is the inequality 3(1 + x) < x + 6 true?

Bond [772]

4 & 5....

i think it is

3 0

3 years ago

Read 2 more answers

4(x+9)=8x-7<br> Solve for x

valentina_108 [34]

Answer:

x = 10.75

Step-by-step explanation:

4(x+9)=8x-7

Step 1: Distribute the 4 to the x and 9

4 * x = 4x

4 * 9 = 36

We now have 4x + 36 = 8x - 7

Step 2: add 7 to both sides

36 + 7 = 43

-7 + 7 cancels out

We now have 4x + 43 = 8x

Step 3 subtract 4x from both sides

4x - 4x cancels out

8x - 4x = 4x

We now have 4x = 43

step 4 divide both sides by 4

4x / 4 ( the 4s cancel out and we're left with x )

43/4 = 10.75

We're left with x = 10.75

3 0

2 years ago

Look at the photo, please.

ruslelena [56]

Answer:

×=6

good luck!!

4 0

3 years ago

Read 2 more answers

A bag has 5 blue marbles, 3 red marbles, and 2 green marbles. We draw two marbles, one at a time, with replacement. What is the

VMariaS [17]

Answer: $\frac{1}{10}$

<u>Step-by-step explanation:</u>

Blue = 5, Red = 3, Green = 2, Total = 10

Probability = First draw and Second draw

= $\frac{5}{10}$ x $\frac{2}{10}$

= $\frac{10}{100}$

= $\frac{1}{10}$

6 0

3 years ago

For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr

viktelen [127]

Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

$3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)$

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

$x_{2}=3x_{1} -2$

substitute in equation (2), we get

$9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k$

we cannot find the value of $x_{1}$ and $x_{2}$ .

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

$3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6$

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

4 0

3 years ago