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pashok25 [27]
3 years ago
12

Explain how to estimate 36.8 + 231 two different ways

Mathematics
1 answer:
larisa [96]3 years ago
5 0
You could do 37+230 or 40 + 235
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Help me find the slope please guys<br> Im struggling
tatuchka [14]

Answer:

negative 1

Step-by-step explanation:

\frac{y2 - y1}{x2 - x1}  = m

the 2 points: (-2,0), (-3,1)

(1-0)/(-3+2)

=-1

m=-1

brainliest please

7 0
3 years ago
Simplify this expression. 12x2(3x4 − 2x)
musickatia [10]

Answer:

36*x^6-24*x^3

Step-by-step explanation:

We can simplify the expressio using the product rule. The exponents will add up when multiplied with each other:

=12*x^2*(3*x^4-2*x)

=12*3*x^(2+4)-12*2*x^(2+1)

=36*x^(6)-24*x^(3)

The answer is B

36*x^6-24*x^3

6 0
3 years ago
Solve this equation: 80 = 3y + 2y + 4 + 1.
Verdich [7]
Let us first write down the given equation.
80 = 3y + 2y + 4 + 1
80 = 5y + 5
80 - 5 = 5y
75 = 5y
Just reversing both sides we get
5y = 75
Now dividing both sides by 5 we get
y = 15
So the value of y is 15. I hope the procedure for solving the problem is clear to you. In future you can solve such problems with ease following the procedure described.



6 0
3 years ago
Read 2 more answers
The larger of two number is 12 more than the smaller number.if the sum of the two numbers is 74, find the two numbers
Mars2501 [29]
<h3><u>The value of the smaller number is 31.</u></h3><h3><u>The value of the larger number is 43.</u></h3>

y = 12 + x

y + x = 74

Since we have a value for y, we can plug it into the second equation

12 + x + x = 74

Subtract 12 from both sides.

x + x = 62

Combine like terms.

2x = 62

Divide both sides by 2.

x = 31


Now that we have a value of x, we can plug it into the original equation to get a value for y.

y = 12 + 31

y = 43

3 0
3 years ago
(8w)^2 without parentheses
Nataly [62]

Answer:

I believe the answer would be 64w2.

Step-by-step explanation:

8 squared is 8 x 8, which equals 64, and then w squared is just w2, since we don't know what it is. Put them together, and the answer is 64w2.

5 0
3 years ago
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