Answer:
Yes, the constant of proportionality is 1.5
Step-by-step explanation:
Answer:
Confidence interval: (21.9, 32.9).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 26 - 1 = 25
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 25 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.485
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 27.4 - 5.5 = 21.9 hours
The upper end of the interval is the sample mean added to M. So it is 27.4 + 5.5 = 32.9 hours
Confidence interval: (21.9, 32.9).
Answer: the store paid $18.3 for the sweater
Step-by-step explanation:
Let x represent the amount that the store paid for the sweater.
A store marks up the price of a sweater by $7.35. This means that the new or current price of the sweater at the store would be
7.35 + x
The total cost of the sweater is 25.65. Therefore, an equation to represent the problem would be
7.35 + x = 25.65
Subtracting 7.35 from the left hand side and the right hand side of the equation, it becomes
7.35 + x - 7.35 = 25.65 - 7.35
x = $18.3
Answer
B DID THE TEST
Step-by-step explanation:
YOU WILL DO YOU GOOD LUCK
Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
