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andrew-mc [135]
3 years ago
15

Evaluate cos((Sin^-1)0)

Mathematics
1 answer:
Kamila [148]3 years ago
4 0
First evaluate
sin^{-1} (0)
what angles in domain of [-pi/2, pi/2] make sin = 0
\theta = 0
Now we can evaluate the cos function:
cos (0) = 1
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