Ask question

Ask question

All categories

Katyanochek1 [597]

3 years ago

6

Tom has 7 more silver dollars than Jimmy. Together they have a total of 71 silver dollars. How many silver dollars does Tom have

?

1 answer:

Eddi Din [679]3 years ago

4 0

Tom has 39 silver dollars. You can do this on your head. Jimmy has 32, and Tom 39.

You might be interested in

A soup can has a diameter of 8 centimeters and a height of 15 centimeters how much soup does the can hold?

Ivan

Answer:

V = 240 pi

Step-by-step explanation:

We want the volume of a cylinder

V = pi r^2 h

We have the diameter and want the radius

r = d/2 = 8/2 = 4

V = pi ( 4)^2 * 15

V = pi * 16* 15

V = 240 pi

Let pi = 3.14

V =753.6 cm^3

Let pi be the pi button

V =753.9822369 cm^3

8 0

3 years ago

Read 2 more answers

Simplify the first expression 5(m+1)-1=

Olegator [25]

Answer:

-0.8/ -4/5

Step-by-step explanation:

5(m+1) -1 = 0

5m +5 -1 = 0

5m +4 =0

5m= -4

m= -4/5

8 0

2 years ago

BRAINLIST HELP ASAPPPP PLEASEEEE DEW IN 5 MINNN

olga55 [171]

Answer:

(x+10)+(×+50)=180(exterior co- interior angel

2x+60=180

2×=180-60

×=120/2

×=60

(6x+3)=(7x-12)(corresponding angle )

3+12=7×-6×

x=15

4x-2=3x-19(vertically opposite angle)

4x-3×=-19+2

x=-17

4 0

2 years ago

{29, 29, 29, 28, 28, 27}

gregori [183]

I think the answer is B Mean or median because there is no outlier.

3 0

2 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago