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Alex_Xolod [135]
4 years ago
8

What do you put as an answer if two numbers have no GCF? 1 or 0

Mathematics
1 answer:
Lostsunrise [7]4 years ago
7 0
Every pair of numbers have a GCF of at least 1.

Therefore, if as you say the numbers have "no GCF", then you should put that their GCF is 1.
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What is the correct definition for tan 0
Reptile [31]
tan\theta=\frac{sin\theta}{cos\theta}\\\\\\Look\ at\ the\ picture.\\\\In\ a\ right\ triangle:\\\\sin\theta=\frac{a}{c};\ cos\theta=\frac{b}{c};\ tan\theta=\frac{a}{b}\\\\\frac{sin\theta}{cos\theta}=\frac{\frac{a}{c}}{\frac{b}{c}}=\frac{a}{c}\times\frac{c}{b}=\frac{a}{b}=tan\theta

3 0
3 years ago
The graph of the function f(x) is shown below.
faust18 [17]
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥

domain is how far the x values go
x is left to right

we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain



range
highest to lowest y value

range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]



Domain=[-3,5)
Range=[-1,3]


B. read above and understand it
5 0
3 years ago
Solve the following equations for the unknown variable.
ser-zykov [4K]

Answer:

4

Step-by-step explanation:1.trust me

2.it will be it

3.just do it

7 0
3 years ago
How much of the circle is shaded? Write your answer as a fraction in simplest form
Valentin [98]

Answer:

11/20

Step-by-step explanation:

Finding the common denominator, which is 20, we convert 1/5 into 4/20 and 1/4 into 5/20. Adding those up, the remainder when subtracted from 1, the total, is 11/20.

8 0
2 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
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