Answer:
If I could have a super power it would be invisibility. Sometimes you wish you weren't there and if you were hiding from someone then they couldn't find you.
Answer:
Explanation:
Determine the number of moles of sodium thiosulfate that are equivalent to one mole of sodium
hypochlorite.
2 S2O3
2− = I−
3 = I2 = ClO−, therefore, for every mole of sodium thiosulfate, we need one half of a
mole of sodium hypochlorite.
2. Calculate the average volume of Na2S2O3
to determine the molarity of the diluted bleach.
16.8 + 17.6
2
= 17.2
3. Use the average volume and molarity of Na2S2O3
to determine the molarity of the diluted bleach.
mol Na2S2O3 = (0.0172)(0.1) = 0.00172
⇓
(0.00172)
2
= 0.000852 mol NaClO
⇓
0.000852
0.025
= 0.341 M NaClO
4. Calculate the average molarity of the commercial bleach before it was diluted.
0.000852 × 4 = 0.0034
0.0034
0.005
= 0.68 M NaClO
5. Assume the density of the commercial bleach is 1.08 g/mL. Calculate the average percent by mass of
NaClO in the commercial bleach.
0.0034 × 74.4424 = 0.2536 g
5mL × 1.08 g/mL = 5.4g
0.2536
5.4 = 4.70%
6. From the label information of the commercial bleach calculate the average deviation of the three
titration values.
|0.047 − 0.060| = 0.013
7. Calculate the percent error of your value.
Answer:The product formed on reaction with hydroxide ion as nucleophile is 2R-hexane-2-ol.
The product formed on reaction with water would be a 50:50 mixture of
2S-hexane-2-ol. and 2R-hexane-2-ol.
Explanation:
2S-iodohexane on reactiong with hydroxide ion would undergo SN² substitution reaction that is substitution bimolecular. Hydroxide ion has a negative charge and hence it is a quite good nucleophile .
The rate of a SN² reaction depends on both the substrate and nucleophile . Here the substrate is a secondary carbon center having Iodine as a leaving group.SN² reaction takes place here as hydroxide ion is a good nucleophile and it can attack the secondary carbon center from the back side leading to the formation of 2R-hexane-2-ol.
In a SN² reaction since the the nucleophile attacks from the back-side so the product formation takes place with the inversion of configuration.
When the same substrate S-2-iodohexane undergoes a substitution reaction with water as a nucleophile then the reaction occurs through (SN¹) substitution nucleophilic unimolecular mechanism .
The rate of a SN¹ reaction depends only on the nature of substrate and is independent of the nature of nucleophile.
The SN¹ reaction is a 2 step reaction , in the first step leaving group leaves leading to the formation of a carbocation and once the carbocation is formed then any weaker nucleophile or even solvent molecules can attack leading the formation of products.
In this case a secondary carbocation would be generated in the first step and then water will attack this carbocation to form the product in the second step.
The product formed on using water as a nucleophile would be a racemic mixture of R and S isomers of hexane -2-ol in 50:50 ratio. The two products formed would be 2R-hexane-2-ol and 2S-hexane-2-ol.
Kindly refer the attachment for reaction mechanism and structure of products.
261.976 which rounds to 261.98(if rounding to the hundredths.