Question

A gas has a volume of 590 ml at a temperature of -55.0°C. What volume will the gas occupy at 30.0°C?

Answer 1

819 ml is the volume the gas will occupy at 30.0°C.

Explanation:

Data given:

initial volume of the gas V1 = 590 ml

initial temperature of the gas T1 = -55 degrees OR 218.15

final volume of the gas V2 = ?

final temperature of the gas T2 = 30 degrees OR 303.15

Charles' Law equation is used to calculate the volume of gas at 30 degrees from the data given in the question.

$\frac{V1}{T1}$= $\frac{V2}{T2}$

V2 = $\frac{V1T2}{T1}$

V2 = $\frac{590 X 303.15}{218.15}$

V2 = 819 ml

The final volume of the gas would be 819 ml.