It would be A because it is 5 units down from the points
Answer:
Even [ 10 is even ] ( 50 ÷ 5 = 10 )
Answer:
BC = 25
Step-by-step explanation:
AB = AC since it is an isosceles triangle
4x+1 = 2x+23
subtract 2x from each side
4x-2x+1 = 2x-2x+23
2x +1 = 23
subtract 1 from each side
2x+1 -1 = 23-1
2x = 22
divide by 2
2x/2 =22/2
x =11
BC = 3x-8
BC = 3(11) -8
BC =33-8
BC = 25
x = –6
Solution:
Given expression is ![\sqrt[3]{x-2}+5=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx-2%7D%2B5%3D3)
.
Step 1: Isolate the radical by subtracting 5 from both sides of the equation.
![\Rightarrow\sqrt[3]{x-2}+5-5=3-5](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%2B5-5%3D3-5)
![\Rightarrow\sqrt[3]{x-2}=-2](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%3D-2)
Step 2: Cube both sides of the equation to remove the cube root.
![\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3](https://tex.z-dn.net/?f=%5CRightarrow%28%5Csqrt%5B3%5D%7Bx-2%7D%29%5E3%3D%28-2%29%5E3)
Cube and cube root get canceled in left side of the equation.
Step 3: To solve for x.
Add 2 on both sides of the equation.
Hence the solution is x = –6.
Answer: 3rd option : Angle 2 and 7
Step-by-step explanation:
Alternate exterior angles are located on the outside of the parallel line on opposite sides.
Therefore, the alternate exetrior angles are 1 and 8 and 2 and 7.
Since there is no option for angle 1 and 8, the correct answer is the 3rd option --> Angle 2 and 7.
