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vfiekz [6]
3 years ago
7

9(6u+5)+2(u-4) need solved

Mathematics
1 answer:
Mazyrski [523]3 years ago
8 0

Answer:

Step-by-step explanation:

Subtract  

6 u  from  2 u .

− 4 u + 9 = 19

Move all terms not containing  u  to the right side of the equation.

− 4 u = 10

Divide each term by  − 4  and simplify.

u = −  \frac{5}{2}

The result can be shown in multiple forms.

Exact Form:

u = −  \frac{5}{2}

Decimal Form:

u =− 2.5

Mixed Number Form:

u = −  2 \frac{1}{2}

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3 years ago
Factor by grouping (write out all of the factoring)<br> 3x^2+18x-6x-36
abruzzese [7]

Answer:

3(x + 6)(x - 2)

Step-by-step explanation:

Given

3x² + 18x - 6x - 36 ← factor out 3 from each term

= 3(x² + 6x - 2x - 12) ( factor the first/second and third/fourth terms )

= 3(x(x + 6) - 2(x + 6)) ← factor out (x + 6) from each term

= 3(x + 6)(x - 2)

6 0
4 years ago
The mean breaking strength of a fiber is required to be at least 150 psi. Past experience has indicated that the standard deviat
Andrews [41]

Answer:

(a) Null hypothesis: The mean breaking strength of a fiber is 150 psi.

Alternate hypothesis: The mean breaking strength of a fiber is less than or equal to 150 psi.

(b) The test statistic is -1.67. There is sufficient evidence to conclude that the mean breaking strength of a fiber is 150 psi.

(c) No, the P value should not be less than the significance level (alpha).

(d) 95% confidence interval for the true mean breaking strength is between a lower limit of 140.71 psi and an upper limit of 154.29 psi.

Step-by-step explanation:

(a) A null hypothesis is a statement from a population parameter which is either rejected or accepted (fail to reject) upon testing. It is expressed using the equality sign.

An alternate hypothesis is also a statement from the population parameter negates the null hypothesis and is accepted if the null hypothesis is rejected. It is expressed using any of the inequality signs.

(b) sample mean = (145+153+150+142)/4 = 590/4 = 147.5 psi

population mean = 150 psi

population sd (sigma) = 3 psia

n = 4

Test statistic (z) = (sample mean - population mean) ÷ (population sd/√n) = (147.5 - 150) ÷ (3/√4) = -2.5 ÷ 1.5 = -1.67

The test is a two-tailed test because the alternate hypothesis is expressed using less than or equal to. For a 5% significance level, critical values are -1.96 and 1.96.

Conclusion:

Fail to reject the null hypothesis because the test statistic -1.67 falls within the region bounded by the critical values.

(c) The P value should not be less than alpha because to fail to reject the null hypothesis using the P value approach, the P value must be greater than alpha (significance level).

(d) Confidence interval is given as mean +/- margin of error (E)

mean = 147.5 psi

sample sd = sqrt[((145-147.5)^2 + (153-147.5)^2 + (150-147.5)^2 + (142-147.5)^2) ÷ 4] = 4.27 psi

n = 4

degree of freedom = n - 1 = 4-1 = 3

confidence level = 95%

critical value (t) corresponding to 3 degrees of freedom and 95% confidence level is 3.182

E = t × sample sd/√n = 3.182×4.27/√4 = 6.79 psi

Lower limit = mean - E = 147.5 - 6.79 = 140.71 psi

Upper limit = mean + E = 147.5 + 6.79 = 154.29 psi

95% confidence interval is (140.71, 154.29)

6 0
4 years ago
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