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shutvik [7]
3 years ago
13

the vertex form of the equation of a parabola is y=(x-5)2+16. what is the standard form of the equation

Mathematics
2 answers:
prohojiy [21]3 years ago
7 0

Answer: y=x^2-10x+41

Step-by-step explanation:

The standard form of a quadratic function is:

y=ax^2+bx+c

You need to remember the square of a binomial:

(a-b)^2=a^2-2ab+b^2

Applying the above, you get:

y=(x-5)^2+16

y=(x^2-2(x)(5)+5^2)+16

Simplify the expression:

y=x^2-10x+25+16

 Now you need to add the like terms.

THerefore, you get:

y=x^2-10x+41

Reika [66]3 years ago
6 0

Answer:

y = x² - 10x + 41

Step-by-step explanation:

The standard form of a quadratic is ax² + bx + c : a ≠ 0

Given

y = (x - 5)² + 16 ← expand (x - 5)²

 = x² - 10x + 25 + 16

 = x² - 10x + 41 ← in standard form

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