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shutvik [7]
3 years ago
13

the vertex form of the equation of a parabola is y=(x-5)2+16. what is the standard form of the equation

Mathematics
2 answers:
prohojiy [21]3 years ago
7 0

Answer: y=x^2-10x+41

Step-by-step explanation:

The standard form of a quadratic function is:

y=ax^2+bx+c

You need to remember the square of a binomial:

(a-b)^2=a^2-2ab+b^2

Applying the above, you get:

y=(x-5)^2+16

y=(x^2-2(x)(5)+5^2)+16

Simplify the expression:

y=x^2-10x+25+16

 Now you need to add the like terms.

THerefore, you get:

y=x^2-10x+41

Reika [66]3 years ago
6 0

Answer:

y = x² - 10x + 41

Step-by-step explanation:

The standard form of a quadratic is ax² + bx + c : a ≠ 0

Given

y = (x - 5)² + 16 ← expand (x - 5)²

 = x² - 10x + 25 + 16

 = x² - 10x + 41 ← in standard form

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What is the answer to 16a5 b3/8ab ?
marishachu [46]

Answer:

When we are dividing exponents, there is this rule:

\frac{a^n}{a^m}=a^{(n-m)}

So, in our case we have this:

\frac{16a^5b^3}{8ab} = \frac{16}{8}a^{(5-1)}b^{(3-1)}=2a^4b^2

5 0
3 years ago
What is the length of if ?<br><br> 8 in.<br> 8.75 in.<br> 10.25 in.<br> 14 in.
quester [9]

Answer:

Diagram attached

AJ = 8.75 in.  

Step-by-step explanation:

Since triangles HBA & HKJ are similar,    

BH/AH = KH/JH  

3 in /5.25 in = 8 in /JH  

JH = 14 in  

JA = JH - AH = JH - 5.25 in = 8.75 in


HJ = 14 in.

AJ = 14 in - 5.25 in  

AJ = 8.75 in.  

7 0
3 years ago
Plz help me!!!
Nadya [2.5K]
To solve this we are going to use the exponential function: f(t)=a(1(+/-)b)^t
where
f(t) is the final amount after t years
a is the initial amount
b is the decay  or grow rate rate in decimal form
t is the time in years

Expression A 
f(t)=624(0.95)^{4t}
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate b, we are going to use the formula: b=|1-base|*100%
b=|1-0.95|*100%
b=0.05*100%
b=5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at t=0
f(t)=624(0.95)^{4t}
f(0)=624(0.95)^{0t}
f(0)=624(0.95)^{0}
f(0)=624(1)
f(0)=624
We can conclude that the initial value of expression A is 624.

Expression B
f(t)=725(1.12)^{3t}
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
b=|1-base|*100%
b=|1-1.12|*100
b=|-0.12|*100%
b=0.12*100%
b=12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at t=0
f(t)=725(1.12)^{3t}
f(0)=725(1.12)^{0t}
f(0)=725(1.12)^{0}
f(0)=725(1)
f(0)=725
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months. 

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0
3 years ago
What equation can you write to solve for x?
KengaRu [80]

Answer:

(3x) ° + (x+ 10)° = 90°

Step-by-step explanation:

(3x) ° + (x+ 10)° = 90°

3x + x + 10 = 90

4x = 90 - 10

4x = 80

x = 20

(3x) ° = 3 x 20 = 60°

(x + 10)° = 20 + 10 = 30°

4 0
3 years ago
Read 2 more answers
Himari gave birth to twins and named them Adrian and Chang. When they were first born, Adrian massed 2.87 kilograms and was 54.5
Likurg_2 [28]

Answer:

The babies massed in total 7.41 kg

Step-by-step explanation:

we know that

To find out the total mass, sum Adrian's mass and Chang's mass

so

The total mass is equal to

2.87+4.54=7.41\ kg

therefore

The babies massed in total 7.41 kg

4 0
3 years ago
Read 2 more answers
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