Hi there, the two numbers would be 5 and 3 because 5+3=8 and 5*3=15. So, the two numbers are 5 and 3
I'm going to reword your question so it's easier to answer. I'm also going to pretend no one has 3 or more accounts because it's irrelevant.
22% have no accounts (220/1000)
What is the probability that 4 or more of the 10 participants has no account?
(220/1000)*(219/999)*(218/998)*(217/997)*(10 choose 4)
<em>p</em> ² + 6 is even if <em>p</em> ² is even (the sum of two even numbers is even), and this happens only if <em>p</em> itself is even, i.e. if <em>p</em> = 2 since 2 is the only even prime.
All other primes <em>p</em> are odd, so <em>p</em> ² would be odd, and adding 6 would not change that (odd + even = odd).
