So, first, you have to find the smallest number that is divisible by both 12 and 10. Which is 60. So, you need 5 boxes of trophies and 6 boxes of stands
Now to get how much it will cost you now multiply the respective costs by the amount of boxes so you get
5 x 10 = 50
6 x 6 = 36
Then you add both
50 + 36 = 86
He will spend a total of $86 on both trophies and stands.
Answer:
20 inches
Step-by-step explanation:
Since the cape is trapezoid shaped and has an area of 600 in², the area of a trapezoid is given by
A =1/2(a + b)h where a = length along the top of the cape = 24 in, b = length along the bottom of the cape = 36 in and h = height of the cape
So, h = 2A/(a + b)
= 2 × 600 in²/(24 in + 36 in)
= 1200 in²/60 in
= 20 in
So, the height of the cape is 20 inches
the discriminant b^2 - 4ac when the equation is in the form of ax^2 +bx+c=0
13x^2-16x = x^2 -x
we need to get in it the standard form
subtract x^2 from each side
12x^2 -16x = -x
add x to each side
12x^2 -15x = 0
12x^2 -15x -0 =0
a=12 b=-15 c=0
b^2 -4ac
the discriminant = b^2
b^2 = (-15)2 = 225
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
The answer is A. You just have to plug in.
Step-by-step explanation:
5x - y/3= 13
(2,-9) and (3,-6)
5(2) - -9/3 = 13
10 + 3 = 13
13 = 13 (true)
5(3) - -6/3= 13
15+ 2 = 13
17 = 13 (wrong)
