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Gre4nikov [31]
3 years ago
5

Help please!!! I really don't understand and I need to pass geometry

Mathematics
1 answer:
Kaylis [27]3 years ago
7 0
Last one is your answer
<CAB = <FDE
You might be interested in
PLEASE I BEG FOR HELP! Find mKNL A. 247 B. 184 C. 196 D. 264
fiasKO [112]

Answer:

D. 264°

Step-by-step explanation:

When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs. Therefore,

60° = 1/2[(18x - 6)° - (5x +17)°]

60° * 2 = (18x - 6 - 5x - 17)°

120° = (13x - 23)°

120 = 13x - 23

120 + 23 = 13x

143 = 13x

143/13 = x

11 = x

x = 11

(18x - 6)° = (18*11-6)°= (198 - 6)° = 192°

(5x +17)° = (5*11 +17)° =(55+17)° = 72°

m (arc KNL) = (18x - 6)° + (5x +17)° = 192° + 72°

m (arc KNL) = 264°

7 0
3 years ago
Best answer gets brainliest
patriot [66]

Question below!

what do you need in order to construct in order to find a point/location that has the same distance away from 2 or more other points

Answer:

Hi, There! Mika-Chan I'm here to help! :)

<u><em>To find the distance from a point to a line, first find the perpendicular line passing through the point. Then using the Pythagorean theorem, find the distance from the original point to the point of intersection between the two lines.</em></u>

<u><em></em></u>

<u><em>Hope this Helps!</em></u>

3 0
3 years ago
PLEASE HELP
Pavel [41]

Answer:

15.06

Step-by-step explanation:

I don't have a step-by-step explanation, but i hope this helps!!!

7 0
3 years ago
Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 )
kati45 [8]

Answer:

y=\frac{1}{2}x-6

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Determine the slope (m)</u>

m=\frac{y_2-y_1}{x_2-x_1} where two points that fall on the line are (x_1,y_1) and (x_2,y_2)

Plug in the given points (2,-5) and (8,-2)

m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{-2-(-5)}{8-2}\\=\frac{-2+5}{8-2}\\=\frac{3}{6}\\=\frac{1}{2}

Therefore, the slope of the line is \frac{1}{2}. Plug this into y=mx+b:

y=\frac{1}{2}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{1}{2}x+b

Plug in one of the given points and solve for b

-5=\frac{1}{2}(2)+b\\-5=1+b

Subtract 1 from both sides to isolate b

-5-1=1+b-1\\-6=b

Therefore, the y-intercept of the line is -6. Plug this back into y=\frac{1}{2}x+b:

y=\frac{1}{2}x+(-6)\\y=\frac{1}{2}x-6

I hope this helps!

6 0
3 years ago
Can someone pls help me
Amanda [17]
<h2>>> Answer </h2>

__________

\:

a² = c² - b²

a² = 9² - (√65)²

a² = 81 - 65

a² = 16

a = √16

a = 4

8 0
3 years ago
Read 2 more answers
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