The Z- score representing the 99th percentile is given by 2.33
Problems of commonly distributed samples can be solved using the z-score formula.
For a set with a standard deviation, the z-score scale X is provided by:
Z = ( x- mean )/ standard deviation
Z-score measures how many standard deviations are derived from the description. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the scale is less than X, that is, the X percentage. Subtract 1 with p-value, we get the chance that the average value is greater than X.
To Find the z-result corresponding to P99, 99 percent of the normal distribution curve.
This is the Z value where X has a p-value of 0.99. This is between 2.32 and 2.33, so the answer is Z = 2.33
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Answer:
x=5/3
Step-by-step explanation:
Subtract x from both sides so you have -3x=-5. Then divide both sides by 3 and you are left with x=5/3
The fifth square root as in a^(1/2)^(1/2)^(1/2)^(1/2)^(1/2)
Well that is equal to a^((1/2)^5) or a^(1/32)
Since a=x^16 in this case and the rule (b^a)^c=b^(a*c) we have:
(x^16)^(1/32)
x^(16/32)
x^(1/2) or if you prefer
√x
Answer:
Step-by-step explanation:
A
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A
