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3 years ago

Length of a rectangle is 4 inches less than twice it’s width of the perimeter is 70 inches what’s the dimensions?

1 answer:

3 0

W= width
L= length= 2W-4
Perimeter= 70

FIND WIDTH:
P= 2(L + W)
P= 2L + 2W
substitute 2W-4 for L
70= 2(2W-4) + 2W
multiply 2 by all in parentheses
70= (2*2W) + (2*-4) + 2W
70= 4W - 8 + 2W
combine like terms
70= 6W - 8
add 8 to both sides
78= 6W
divide both sides by 6
13= W

FIND LENGTH:
substitute w=13 to find width
L= 2W-4
L= 2(13)-4
L= 26-4
L= 22

CHECK:
P= 2(L + W)
70= 2(22 + 13)
70= (2*22) + 2(13)
70= 44 + 26
70= 70

ANSWER:
length= 22 inches
width= 13 inches

Hope this helps! :)

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Step-by-step explanation:

Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"

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From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this: $(x+8)^2 +(y-4)^2 = r^2$

If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for $r^2$

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And if we replace the second point we got this:

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And for the third point we have:

$(-8+8)^2 +(-1-4)^2 = 25 =r^2$

And we got the same result.

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</span>
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