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sergij07 [2.7K]
3 years ago
11

Given a 30-60-90 triangle with a long leg of 9 inches, determine the length of the hypotenuse

Mathematics
1 answer:
lianna [129]3 years ago
6 0

A Quick Guide to the 30-60-90 Degree Triangle

The 30-60-90 degree triangle is in the shape of half an equilateral triangle, cut straight down the middle along its altitude. It has angles of 30°, 60°, and 90°. In any 30-60-90 triangle, you see the following: The shortest leg is across from the 30-degree angle, the length of the hypotenuse is always double the length of the shortest leg, you can find the long leg by multiplying the short leg by the square root of 3.

Note: The hypotenuse is the longest side in a right triangle, which is different from the long leg. The long leg is the leg opposite the 60-degree angle.

Two of the most common right triangles are 30-60-90 and the 45-45-90 degree triangles. All 30-60-90 triangles, have sides with the same basic ratio. If you look at the 30–60–90-degree triangle in radians, it translates to the following:

30, 60, and 90 degrees expressed in radians.

The figure illustrates the ratio of the sides for the 30-60-90-degree triangle.

A 30-60-90-degree right triangle.

A 30-60-90-degree right triangle.

If you know one side of a 30-60-90 triangle, you can find the other two by using shortcuts. Here are the three situations you come across when doing these calculations:

Type 1: You know the short leg (the side across from the 30-degree angle). Double its length to find the hypotenuse. You can multiply the short side by the square root of 3 to find the long leg.

Type 2: You know the hypotenuse. Divide the hypotenuse by 2 to find the short side. Multiply this answer by the square root of 3 to find the long leg.

Type 3: You know the long leg (the side across from the 60-degree angle). Divide this side by the square root of 3 to find the short side. Double that figure to find the hypotenuse.

Finding the other sides of a 30-60-90 triangle when you know the hypotenuse.

Finding the other sides of a 30-60-90 triangle when you know the hypotenuse.

In the triangle TRI in this figure, the hypotenuse is 14 inches long; how long are the other sides?

Because you have the hypotenuse TR = 14, you can divide by 2 to get the short side: RI = 7. Now you multiply this length by the square root of 3 to get the long side:

The long side of a 30-60-90-degree triangle.

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Find the area<br> cant solve
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Answer:

36in²

Step-by-step explanation:

<h3>Area of the White Region: </h3>

A = l * w

The rectangle is 3 by 2.

A = 3 * 2

A = 6

The white part of the rectangle is 6in².

<h3>Area of the blue region:</h3>

A = l * w

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Please help me out guys. The photo will show you what to do. 50 points cause I need it done fast
Nonamiya [84]

Answer:

a) starting height: 5.5 ft

b) hang time: 5.562 seconds

c) maximum height: 126.5 ft

d) time to maximum height: 2.75 seconds

Step-by-step explanation:

a) The starting height is the height at t=0.

h(0) = -16·0 +88·0 +5.5

h(0) = 5.5

The starting height is 5.5 feet.

__

b) The ball is in the air between t=0 and the non-zero time when h(t) = 0. We can find the latter by solving ...

-16t^2 + 8t +5.5 = 0

t^2 -(11/2)t = 5.5/16 . . . . . subtract 5.5, then divide by -16

t^2 -(11/2)t +(11/4)^2 = (5.5/16) +(11/4)^2 . . . . complete the square

(t -11/4)^2 = 126.5/16 . . . . . . . . . . . . . . . . . . . . call this [eq1] for later use

t -11/4 = √7.90625

t = 2.75 +√7.90625 ≈ 5.562

The ball will be in the air about 5.562 seconds.

__

c) If we multiply [eq1] above by -16 and add the constant on the right, we get the vertex form of the height equation:

h(t) = -16(t -11/4) +126.5

The vertex at (2.75, 126.5) tells us ...

The maximum height of the ball is 126.5 feet.

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d) That same vertex point tells us ...

The maximum height will be reached at t = 2.75 seconds.

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If you really need answers fast, a graphing calculator can give them to you in very short order (less than a minute).

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1. The prism-shaped roof has equilateral triangular bases. Create an equation that models the height of one of the roof's triang
lana66690 [7]

Answer:

h=\frac{\sqrt{3}}{2}b\ units    

Step-by-step explanation:

we know that

An equilateral triangle has three equal sides and three equal interior angles (the measure of each interior angle is equal to 60 degrees)

see the attached figure to better understand tyhe problem

Let

h ----> the height of an equilateral triangle

b ---> the length side of an equilateral triangle

In the right triangle ABD

Applying the Pythagorean Theorem

AB^2=AD^2+BD^2

substitute the given values

b^2=(\frac{b}{2})^2+h^2  

b^2=\frac{b^2}{4}+h^2

h^2=b^2-\frac{b^2}{4}

h^2=\frac{3}{4}b^2

square root both sides

h=\frac{\sqrt{3}}{2}b\ units      

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