All categories

3 years ago

Ed is 7 years older than Ted. Ed’s age is also 3/2 times Ted’s age. How old are Ed and Ted?

Mathematics

1 answer:

Troyanec [42]3 years ago

7 0

Ed will be ten and Ted will be 3

You might be interested in

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

4 years ago

Vika [28.1K]

Length of bc is 8
hope this helps :))

3 0

2 years ago

A triangle has a base of 4x-7 and a height of 2x + 3. Find the area.

wolverine [178]

Answer:

area = ‐11

Step-by-step explanation:

hope this is correct and helps

7 0

3 years ago

What function was used to make that pattern

Semenov [28]

Answer:

Step-by-step explanation:

The differences in the terms of f(x) are + 3, + 5, + 7

Since the differences are not constant the relationship is not linear

Note the differences in the differences are + 2, + 2,

The second differences are constant indicating a quadratic relationship

Note the relationship between x and f(x)

x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)

x = 2 → 2² = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)

x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)

x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)

Thus f(x) = x² + 5 → B

3 0

3 years ago

How do I do this???!????

Marina CMI [18]

Can you resubmit your question so that I can give you a reasonable answer

4 0

4 years ago