Answer:
-3
Step-by-step explanation:
Answer:
since you recorded the first marble then replaced it, you drew 10 blue marbles, so therefore we can predict the next marble you drew, was blue.
Step-by-step explanation:
Answer:
79 inches
Step-by-step explanation:
2 m * 100cm/m * 1 in/2.54cm = 78.7401574803 in
rounded
79 inches
1/2r+2(3/4r-1)=1/4r+6
2r-2=1/4r+6
2r=1/4r+8
7/4r=8
7r=32
r=32/7
Answer:

Step-by-step explanation:
Given:

1.

2.

3.

4.

5.

6.

7.

8.
