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3 years ago

What is the value of (1+i) (1 - 1) 2 – 3 ?

Mathematics

2 answers:

nikitadnepr [17]3 years ago

8 0

Answer:

Step-by-step explanation:

(a + b)(a-b) = a² - b²

i² = -1

(1 + i)(1-i) = 1² - i² = 1 - (-1) = 1 +1 = 2

$\frac{(1+i)(1-i)}{2-3i}=\frac{2}{2-3i}\\\\=\frac{2*(2+3i)}{(2-3i)(2+3i)}\\\\=\frac{2*2+2*3i}{2^{2}-(3i)^{2}}\\\\=\frac{4+6i}{4-3^{2}*i^{2}}\\\\\frac{4+6i}{4-9*(-1)}\\\\=\frac{4+6i}{4+9}\\\\=\frac{4+6i}{13}\\\\=\frac{4}{13}+\frac{6}{13}i$

fiasKO [112]3 years ago

7 0

Answer:

hi! your answer should be D

Step-by-step explanation:

I plugged the equation into a calculator and got D.

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Which statement is true? A. A sample statistic can never be equal to the population parameter. B. Point estimates are defined fo

stich3 [128]

Answer:

Step-by-step explanation:

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3 years ago

2 7/8 divided by 2 1/4

trasher [3.6K]

2 7/8 = 23/8

2 1/4 = 9/4

23/8 / 9/4 =

23/8 * 4/9 = 92/72 = 1 20/72 = 1 5/18

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3 years ago

Can someone please explain this by step by step? And give me the answer

AURORKA [14]

Answer:

we know that q=-18

So if we see the fraction below it says q/3

We know that q is -18

Therefore, you substitute it in for q and you get

-18/3 which equals -6

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3 years ago

Can someone help thanks

Salsk061 [2.6K]

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since the problem gave you the base area, that would be the l *w

so now you would need to multiply the base area by the height, then divide by 3

16 * 15 = 240

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3 years ago

Convert the inequalities into equations, and then use the substitution method to find four possible vertices in the form (x, y,

alina1380 [7]

Answer:

For 2x + 5y < 100, x + y < 30. Vertices : (50,0) , (0,20) , (35,0) , (0,35) , (25,0)

Step-by-step explanation:

Considering inequality equations

i) 2x + 5y < 100 ;

ii) x + y < 35

Concerting them to equality conditions

i) 2x + 5y =100.

Intercepts : If y = 0, x = 50. So, (50,0). If x = 0, y = 20. So, (0,20)

ii) x + y = 35. Intercepts :

Intercepts : If y = 0, x = 35. So, (35,0). If x = 0, y = 35 So, (0,35)

Solving them as per equality (with substitution)

From ii), x = 35 - y . Putting the value in i)

2 (35 - y) + 5y = 100 → 70 - 2y + 5y = 100 → 70 + 3y = 100

3y = 100 - 70 → 3y = 30 → y = 30 / 3 = 10

Putting y = 10 in ii) : x = 35 - 10 = 25

As per the 'less than' inequalities : the inner 'towards origin' area from both lines is in common shaded area.

Henceworth, vertices are : (50,0) , (0,20) , (35,0) , (0,35) & intersection (25,0)

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3 years ago