Question

What is the value of (1+i) (1 - 1) 2 – 3 ?

Answer 1

Answer:

Step-by-step explanation:

(a + b)(a-b) = a² - b²

i² = -1

(1 + i)(1-i) = 1² - i²   = 1 - (-1) = 1 +1 = 2

$\frac{(1+i)(1-i)}{2-3i}=\frac{2}{2-3i}\\\\=\frac{2*(2+3i)}{(2-3i)(2+3i)}\\\\=\frac{2*2+2*3i}{2^{2}-(3i)^{2}}\\\\=\frac{4+6i}{4-3^{2}*i^{2}}\\\\\frac{4+6i}{4-9*(-1)}\\\\=\frac{4+6i}{4+9}\\\\=\frac{4+6i}{13}\\\\=\frac{4}{13}+\frac{6}{13}i$

Answer 2

Answer:

hi! your answer should be D

Step-by-step explanation:

I plugged the equation into a calculator and got D.