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Levart [38]
3 years ago
6

Evaluate (2/3) to the third power + 2 + 7/9

Mathematics
2 answers:
Gelneren [198K]3 years ago
8 0
(2/3) ^ 3 = (2*2*2) / (3*3*3) = 8 / 27
2 and 7/9 = (18 + 7)/9 = 25 /9

Add these two together
8/27 + 25/9 = 8/27 + 25*3/(9*3)
8/27 + 75/27 = 83/27 <<<< answer 1

The result 
83 / 27 = 3 with a remainder of 2 = 3 2/27 <<<<< answer 2
83/ 27 = 3.074074 <<<<<<<< answer 3

Note
I don't know which answer to pick. I would suspect the first one, but it depends on what you have been told.
Jobisdone [24]3 years ago
5 0
We have 8/27 + 25/9 = 24/81 + 225/81 = 249/81 = 3.07;
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Newly purchased tires of a particular type are supposed to be filled to a pressure of 30 psi. Let m denote the true average pres
dimulka [17.4K]

Answer:

a) 48.21 %

b) 45.99 %

c) 20.88 %

d) 42.07 %

e) 50 %

Note: these values represent differences between z values and the mean

Step-by-step explanation:

The test to carry out is:

Null hypothesis  H₀    is                           μ₀ = 30  

The alternative hypothesis                      m  ≠ 30

In which we already have the value of z for each case therefore we look  directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)

a)  z = 2.1   correspond to  0.9821  but mean value is ubicated at 0.5 then we subtract    0.9821 - 0.5  and get 0.4821   or 48.21 %

b)  z = -1.75   P(m) = 0.0401     That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %

c)  z = -.55    P(m) = 0.2912    and this value  for same reason as before is 0.5 - 0.2912 = 0.2088  or 20.88 %

d)  z = 1.41     P(m) = 0.9207    0.9207 -0.5     0.4207  or  42.07 %

e)  z = -5.3   P(m) = 0    meaning there is not such value in z table is too small to compute  and difference to mean value will be 0.5  

d)  z= 1.41      P(m) =

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3 years ago
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