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lbvjy [14]
3 years ago
14

This is hard can someone help me please

Mathematics
2 answers:
Vesna [10]3 years ago
7 0
0.04035. that's it I think
Bond [772]3 years ago
7 0
Te answer is 410.25 or 410 1/4
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y=550+30?x this doesnt make sense

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Find the slope-intercept form of a line that goes through the point (-1,3) and is parallel to -x+3y=12
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First, I would simplify the given equation to find the slope of the parallel line as it will be the same for the line we are looking for.
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3 years ago
What is 2.52 Divided By 50.8
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3 years ago
Read 2 more answers
Suppose f is a function of one variable that has a continuous second derivative. Show that for any constants a and b, the functi
salantis [7]

Answer:

We can find the solution using chain rule,

For instance, if u(x,y) = f(ax+by), then

u_{x}(x,y) = a f^{'} (ax+by)  which represents derivative of x with respect to x

and then derivative of u_{x}(x,y) with respect to y is

u_{xy}(x,y) = (ab)^2 (f^{''} (ax+by))^2,  

Now, the derivative of u_{x}(x,y) with respect to x, which is the second derivative, which is

u_{xx}(x,y) = a^2 f^{''} (ax+by)

and the derivative u_{y}(x,y) and   u_{yy}(x,y) are

u_{y}(x,y) = b f^{'} (ax+by),

u_{yy}(x,y) = b^2 f^{''} (ax+by)

Finally, the solution of PDE is

u_{xx}(x,y) u_{yy}(x,y) - u_{xy} ^2 (x,y)

= (a^2 f^{''} (ax+by)) (b^2 f^{''} (ax+by)) - (ab)^2 (f^{''} (ax+by))^2

= (ab)^2 (f^{''} (ax+by))^2) - (ab)^2 (f^{''} (ax+by))^2

= 0,

As the PDE is equal to 0, it means the function u(x,y) = f(ax+by) is the solution of the given PDE.

6 0
4 years ago
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