Please help me on this question, if your smart in math.
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Given a Venn diagram showing the number of students that like blue uniform only as 32, the number of students that like gold uniform only as 25, the number of students that like blue and gold uniforms as 12 and the number of students that like neither blue nor gold uniform as 6.
Thus, the total number of students interviewed is 75.
Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.
From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by
Therefore, a = 33% to the nearest percent.
Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From the Venn, diagram, the number of students that like blue uniform only as 32, thus the relative frequency of the students that like gold but not blue is given by
Therefore, b = 43% to the nearest percent.
Thus, the total number of students interviewed is 75.
Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.
From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by
Therefore, a = 33% to the nearest percent.
Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From the Venn, diagram, the number of students that like blue uniform only as 32, thus the relative frequency of the students that like gold but not blue is given by
Therefore, b = 43% to the nearest percent.
Answer:
Part 5) The roots are x=-3 and x=1.5
Part 6) The solution on a number line is the shading area below of the line y=-1/3 (close circle)
Step-by-step explanation:
for the system of equations
the three matrices needed to use Cramer's Rule are:
.
To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.
.
The value of the determinants are shown below.
The value of y is .