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3 years ago

7

Solve for x (13x + 2) (5x - 7) (3x - 4) Thank you

2 answers:

Law Incorporation [45]3 years ago

5 0

$\huge \bf༆ Answer ༄$

As we know, sum of interior angles of a triangle is 180°

that is ~

$\sf13x + 2 + 5x - 7 + 3x - 4 = 180$

$\sf21x - 9 = 180$

$\sf21x = 180 + 9$

$\sf x = \dfrac{189}{21}$

$\sf x = 9 \degree$

Hence, value of x is 9°

AlexFokin [52]3 years ago

3 0

Answer:

x = 9

Step-by-step explanation:

<u>Sum of interior angles is 180:</u>

(13x + 2) + (5x - 7) + (3x - 4) = 180
21x - 9 = 180
21x = 189
x = 189/21
x = 9

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What is the measure of XYZ?<br> А. 74°<br> В. 296°<br> с. 32°<br> D. 148°

LenaWriter [7]

Answer:

∠XYZ = 74°

Step-by-step explanation:

∠XYZ = $\frac{1}{2}$ arcXZ

∠XYZ = $\frac{1}{2}$ 148°

∠XYZ = 74°

8 0

3 years ago

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Daniel bought four bags of potatoes. The weight of the first bag was 2.6 pounds. The second bag weighed 0.4 pound less than twic

ipn [44]

Answer:

Average weight of the bags of potatoes is 3.8 pounds.

Step-by-step explanation:

Given:

Weight of the first bag, $W_{1}=2.6$ pounds.

Weight of the second bag is 0.4 pounds less than twice the weight of first bag. This means,

$W_{2}=2W_{1}-0.4=2(2.6)-0.4=5.2-0.4=4.8\textrm{ pounds}$

Weight of the third bag is 0.6 pounds more than that of the first bag. This means,

$W_{3}=W_{1}+0.6=2.6+0.6=3.2\textrm{ pounds}$

Weight of the fourth bag is 0.3 pounds less than that of the second bag. This means,

$W_{4}=W_{2}-0.3=4.8-0.3=4.5\textrm{ pounds}$

Therefore, the average weight of the bags of potatoes is given as the sum of all the weights and then divide the sum by 4. Therefore,

$W_{average}=\frac{W_{1}+W_{2}+W_{3}+W_{4}}{4}=\frac{2.6+4.8+3.2+4.5}{2}=\frac{15.1}{4}=3.775\approx 3.8$

Therefore, average weight of the bags of potatoes is 3.8 pounds.

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3 years ago

Alinara [238K]

It is D. ,that one makes the most sense to me

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3 years ago

A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Portland. The stu

iVinArrow [24]

Answer:

$-0.061 < P_1 -P_2< 0.025$

Step-by-step explanation:

Give data:

$n_1 = 350$

$n_2 =250$

$x_1 = 23$

$x_2 = 21$

$\hat{P} 1 = \frac{x_1}{n_1} = \frac{23}{350} = 0.066$

$\hat{P} 2 = \frac{x_2}{n_2} = \frac{21}{250} = 0.084$

for 95% confidence interval

$\alpha = 1 - 0.95 = 0.05 and \alpha/2 = 0.025$

$z_{\alpha/2} = 1.96$ from standard z- table

confidence interval for P_1 and P_2 is

$\hat{P} 1 - \hat{P} 2 \pm z_{\alpja/2} \sqrt{\frac{\hat{P} 1(1-\hat{P} 1)}{n_1} +\frac{\hat{P} 2(1-\hat{P} 2)}{n_2}}$

$(0.066 - 0.084) \pm 1.96 \sqrt{\frac{0.066(1-0.066)}{350} +\frac{0.084(1-0.084)}{250}}$

$-0.018 \pm 0.043$

confidence interval is

$-0.018 - 0.043 < P_1 -P_2$

$-0.061 < P_1 -P_2< 0.025$

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3 years ago

What is the answer to this decimal problem 0.32÷n=0.032

11111nata11111 [884]

10 because you know that the decimal moves one to the left if you are dividing by ten and one to the right if you are multiplying by ten.

Check your work. 0.32 divided by 10 is 0.032

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3 years ago

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