With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.
With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.
1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.
P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13
So the answer is B.
Answer:
C
Step-by-step explanation:
Attached Picture.......
Answer:
x = 5
Step-by-step explanation:
have a nice day
brainliest?
Answer:
0.51 or 51%.
Step-by-step explanation:
If there were 100 students in the school, then 38 have a dog 24 a cat and 11 have both.
So there are 38 - 11 = 27 who only have a dog and 24-11 = 13 who only have a cat.
So total number having a pet = 27+11+13
= 51 students.
So Prob(You will choose a student with a pet) = 51%.
Drawing a Venn diagram would help to answer this and make it clearer.
