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Naddik [55]
3 years ago
10

PLEASE , ANYONE SAY THE ANSWER!! PLEASE I NEED IT , PLS ANYONE HELP

Mathematics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

<h2><em><u>B. 20% because he only got 400 back</u></em><em><u> </u></em></h2>

<em>Pls</em><em> </em><em>Mark</em><em> </em><em>me</em><em> </em><em>as</em><em> </em><em>brainliest</em><em> </em>

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Step-by-step explanation:

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Write the equation of the line that passes through the given points. (-1,16.5) And (0,6.5)
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I need help with 24 plzz
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Answer: -60

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3 years ago
Form an equivalent expression 5x + 9z -x
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3 0
3 years ago
Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In​ addition, there is
Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so P(A) = 0.13.

In​ addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. P(B/A) is the probability that the person is a male, given that he/she jogs. So P(B/A) = 0.156

The Bayes theorem states that:

P(B/A) = \frac{P(A \cap B)}{P(A)}

In which P(A \cap B) is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

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P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0
3 years ago
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