Please solve fast please
1 answer:
Answer:
see explanation
Step-by-step explanation:
Using identities
sec²x = tan²x + 1
cosec²x = cot²x + 1
cos²x =
(1)
sin²θ +
= sin²θ + cos²θ = 1
(2)
9sec²θ - 9tan²θ
= 9sec²θ - 9(sec²θ - 1)
= 9sec²θ - 9sec²θ + 9
= 9
(3)
- 8cot²A + 8cosec²A
= - 8cot²A + 8(cot²A + 1)
= - 8cot²A + 8cot²A + 8
= 8
(4)
- 10cosec²β + 10cot²β
= - 10(cot²β + 1) + 10cot²β
= - 10cot²β - 10 + 10cot²β
= - 10
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Answer:
4.5 sq. units.
Step-by-step explanation:
The given curve is
⇒ ...... (1)
This curve passes through (0,0) point.
Now, the straight line is y = 3x - 6 ....... (2)
Now, solving (1) and (2) we get,
⇒ (y - 3)(y + 2) = 0
⇒ y = 3 or y = -2
We will consider y = 3.
Now, y = 3x - 6 has zero at x = 2.
Therefor, the required are =
=
=
= 6 - 1.5
= 4.5 sq. units. (Answer)