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Lesechka [4]
3 years ago
5

Given thatF1 = 50 Nr1= 3 mr2 = 2 mThe beam does not move. How large is force F2?​

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

6m

Step-by-step explanation:

If it doesn't move it's just the same force

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Two planes left an airport at noon. One flew east at a certain speed and the other flew west at twice the speed. The planes were
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The plane flying west was flying at 600 miles per hour and the plane flying east was flying 300 miles per hour
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4 years ago
The initial population of atown is 3500 and it grows with a doubling time of 12 years. Determine how long it will take for the p
Maslowich
After 12 years
3500 * 2 = 7000

after 24 years
7000 * 2 = 14000

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so the answer is 24 years
4 0
3 years ago
If f(x)= 3x + 10x and g(x)=5x - 3 find (f+g)(x)
Illusion [34]

Answer:

18x-3

Step-by-step explanation:

f(x)= 3x + 10x

g(x)=5x - 3

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6 0
3 years ago
Help me with this question please!
BigorU [14]

Answer:

c = 40d+20

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58​-by-58 squar
Savatey [412]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

4 0
3 years ago
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