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sveta [45]
3 years ago
13

Emma Sanchez is currently renting an apartment for $725 per month and paying $275 annually for renter’s insurance. She just foun

d a small townhouse she can buy for $185,000. She has enough cash for a $10,000 down payment and $4,000 in closing costs. Her bank is offering 30-year mortgages at 5 percent per year. Emma estimated the following costs as a percentage of the home’s price: property taxes, 2.5 percent; homeowner’s insurance, 0.5 percent; and maintenance, 0.7 percent. She is in the 22 percent tax bracket and does not plan to itemize deductions on her taxes. Emma estimates that the value of the home will appreciate 2 percent per year.
Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:

Annual Cost of Rent: $725*12=8700

Add: Renter's Insurance=$275

Total Cost=$8,975

Now if she purchased a house then let's see how much annual cost she need to bear:

EMI=$185000-$10,000=$175000/Total PVIF @5% for 30Years

EMI=$939.44

Hence. Annually it would be $939.44*12=$11273.28

So, it is quite clear that by purchasing the owned home Emma needs to bear extra cost of $2298.28 per year apart from the yearly expenditure that is property taxes insurance and maintenance which is of 10% of total cost of the house that is $18,500($185000*10%).

Hence, to purchase a house is not feasible and to go for the rent option is more viable for Emma.

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A survey of 700 adults from a certain region​ asked, "What do you buy from your mobile​ device?" The results indicated that 59​%
Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are  (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }

where p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}  

on calculation we get   p = 0.56    

now q =1-p = 1-0.56=0.44

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

<u></u>

3 0
3 years ago
Ariana owns a food truck that sells tacos and burritos. She sells each taco for $4 and each burrito for $8.25. Ariana must sell
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Answer:

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Step-by-step explanation:

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2 years ago
Which expression is equivalent to
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Answer:

option D is the correct answer

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3 0
2 years ago
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Write an algorithm to solve the problem with long division. Answer in at least 3 complete sentences.​
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Answer:

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Step-by-step explanation:

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What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
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Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

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