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3 years ago

What does the numerator of the fraction 5/6 mean?

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Answer:

the numerator is 5

Step-by-step explanation:

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Let f(x) = cos(x). Use Addition or Subtraction Formulas to show the following.

uysha [10]

Answer:

First blank is cos(h)cos(x)

Second blank is sin(x)

Step-by-step explanation:

Look up the identity and apply it here

7 0

2 years ago

ZanzabumX [31]

Answer:

To create function h, function f was translated 2 units right , translated 4 units up and reflected across the x axis

Step-by-step explanation:

Given

$f(x) = x^3$

$h(x) =-(x + 2)^3 - 4$

Required

Complete chart

First: f(x) was translated right by 2 units

The rule of right translation is $(x,y) \to (x + 2,y)$

So, we have:

$f'(x) = f(x + 2)$

$f'(x) = (x + 2)^3$

Next: f'(x) was translated up by 4 units

The rule of down translation is $(x,y) \to (x,y+4)$

So, we have:

$f"(x) = f'(x) +4$

$f"(x) = (x + 2)^3 +4$

Lastly, f"(x) was reflected across the x-axis;

The rule of this reflection is: $(x,y) \to (x,-y)$

So, we have:

$h(x) = -f"(x)$

$h(x) = -[(x+2)^3 + 4]$

Remove bracket

$h(x) = -(x+2)^3 - 4$

8 0

2 years ago

The Venn diagram displays the number of employees at United Accounting Firm, in hundreds, who travel to work by a given method a

Svetlanka [38]

Answer:

Step-by-step explanation:

if 3500 employees work at the firm, the you minus the total amount of employees taking either a car or the train from 3500 (3500-2300 = 1200)

3 0

3 years ago

Is (3,-2) a solution to the system below? How do you know?

cricket20 [7]

Step-by-step explanation:

you know by using the x and y coordinates of the point in the equations and see, if both equations are still true.

if yes, it was a solution, and if just only one is false, then it was not a solution.

(3, -2) in

y + 4x = 10

5x - y = 13

so,

-2 + 4×3 = 10

-2 + 12 = 10

10 = 10 true

5×3 - (-2) = 13

15 + 2 = 13

17 = 13 false

so, it was NOT a solution.

3 0

2 years ago

Log14/3 +log11/5-log22/15=log

Tamiku [17]

Answer:

$log7$

Step-by-step explanation:

when adding logs, apply the log rule: $\log _a\left(x\right)+\log _a\left(y\right)=\log _a\left(xy\right)$

∴ $\log\left(\frac{14}{3}\right)+\log\left(\frac{11}{5}\right)=\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)$

when subtracting logs, apply the log rule: $\log _a\left(x\right)\:-\:\log _a\left(y\right)=\log _a\left(\frac{x}{y}\right)$

$\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)-\log\left(\frac{22}{15}\right)=\log\left(\frac{\frac{14}{3}\cdot \frac{11}{5}}{\frac{22}{15}}\right)\\\\=\log\left(7\right)$

5 0

2 years ago

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