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3 years ago

What does the numerator of the fraction 5/6 mean?

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Answer:

the numerator is 5

Step-by-step explanation:

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I forgot how to do this n they didn’t put an example help me lol

lyudmila [28]

Answer:

60 $m^2$

Step-by-step explanation:

First, find the area of the square as it the missing piece wasn't missing.

8 x 9 = 72 $m^2$

Then, find the area of the missing section.

3 x 4 = 12 $m^2$

Finally, subtract 12 $m^2$ from 72 $m^2$ and you get 60 $m^2$

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2 years ago

twenty students in A and 20 students in class B were asked how many hours they took to prepare for an exam.The data sets represe

SSSSS [86.1K]

Answer:

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Step-by-step explanation:

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2 years ago

Evaluate the function for f(3).<br> f(x) = -3x - 8

scoundrel [369]

If 3 is x that means y is -17 so that mean f=-17/3

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2 years ago

A mosquito collides head-on with a car traveling 60 mph. Is the force of the mosquito on the car larger than, smaller than, or e

nirvana33 [79]

Smaller the mosquitoes possibly fly only 9mph a car coming at 60 would destroy mosquito obviously the force of a moving object will move it

5 0

3 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

10 months ago